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二項分布(基礎)

Total questions: 11

Worksheet time: 11mins

Name
Class
Date
1.

有5題4選1的單選題,某生每題皆隨意選擇一個選項作答。已知每題答對與否為獨立事件,求恰答對2題的機率?

a)

C55(14)5(34)0=11024C_5^5\left(\frac{1}{4}\right)^5\left(\frac{3}{4}\right)^0=\frac{1}{1024}

b)

C45(14)4(34)1=151024C_4^5\left(\frac{1}{4}\right)^4\left(\frac{3}{4}\right)^1=\frac{15}{1024}

c)

C25(14)2(34)3=2701024C_2^5\left(\frac{1}{4}\right)^2\left(\frac{3}{4}\right)^3=\frac{270}{1024}

d)

C35(14)3(34)2=901024C_3^5\left(\frac{1}{4}\right)^3\left(\frac{3}{4}\right)^2=\frac{90}{1024}

2.

有5題4選1的單選題,某生每題皆隨意選擇一個選項作答。已知每題答對與否為獨立事件,求5題全答對的機率?

a)

C55(14)5(34)0=11024C_5^5\left(\frac{1}{4}\right)^5\left(\frac{3}{4}\right)^0=\frac{1}{1024}

b)

C45(14)4(34)1=151024C_4^5\left(\frac{1}{4}\right)^4\left(\frac{3}{4}\right)^1=\frac{15}{1024}

c)

C25(14)2(34)3=2701024C_2^5\left(\frac{1}{4}\right)^2\left(\frac{3}{4}\right)^3=\frac{270}{1024}

d)

C35(14)3(34)2=901024C_3^5\left(\frac{1}{4}\right)^3\left(\frac{3}{4}\right)^2=\frac{90}{1024}

3.

有5題4選1的單選題,某生每題皆隨意選擇一個選項作答。已知每題答對與否為獨立事件,求恰答對4題的機率?

a)

C55(14)5(34)0=11024C_5^5\left(\frac{1}{4}\right)^5\left(\frac{3}{4}\right)^0=\frac{1}{1024}

b)

C45(14)4(34)1=151024C_4^5\left(\frac{1}{4}\right)^4\left(\frac{3}{4}\right)^1=\frac{15}{1024}

c)

C25(14)2(34)3=2701024C_2^5\left(\frac{1}{4}\right)^2\left(\frac{3}{4}\right)^3=\frac{270}{1024}

d)

C35(14)3(34)2=901024C_3^5\left(\frac{1}{4}\right)^3\left(\frac{3}{4}\right)^2=\frac{90}{1024}

4.

有5題4選1的單選題,某生每題皆隨意選擇一個選項作答。已知每題答對與否為獨立事件,求恰答對3題的機率?

a)

C55(14)5(34)0=11024C_5^5\left(\frac{1}{4}\right)^5\left(\frac{3}{4}\right)^0=\frac{1}{1024}

b)

C45(14)4(34)1=151024C_4^5\left(\frac{1}{4}\right)^4\left(\frac{3}{4}\right)^1=\frac{15}{1024}

c)

C25(14)2(34)3=2701024C_2^5\left(\frac{1}{4}\right)^2\left(\frac{3}{4}\right)^3=\frac{270}{1024}

d)

C35(14)3(34)2=901024C_3^5\left(\frac{1}{4}\right)^3\left(\frac{3}{4}\right)^2=\frac{90}{1024}

5.

有6題是非題,某生每題皆隨意作答。已知每題答對與否皆為獨立事件,求恰答對3題?

a)

C06(12)0(12)6=164C_0^6\left(\frac{1}{2}\right)^0\left(\frac{1}{2}\right)^6=\frac{1}{64}

b)

C16(12)1(12)5=664C_1^6\left(\frac{1}{2}\right)^1\left(\frac{1}{2}\right)^5=\frac{6}{64}

c)

C26(12)2(12)4=1564C_2^6\left(\frac{1}{2}\right)^2\left(\frac{1}{2}\right)^4=\frac{15}{64}

d)

C36(12)3(12)3=2064C_3^6\left(\frac{1}{2}\right)^3\left(\frac{1}{2}\right)^3=\frac{20}{64}

6.

有6題是非題,某生每題皆隨意作答。已知每題答對與否皆為獨立事件,求恰答對2題?

a)

C06(12)0(12)6=164C_0^6\left(\frac{1}{2}\right)^0\left(\frac{1}{2}\right)^6=\frac{1}{64}

b)

C16(12)1(12)5=664C_1^6\left(\frac{1}{2}\right)^1\left(\frac{1}{2}\right)^5=\frac{6}{64}

c)

C26(12)2(12)4=1564C_2^6\left(\frac{1}{2}\right)^2\left(\frac{1}{2}\right)^4=\frac{15}{64}

d)

C36(12)3(12)3=2064C_3^6\left(\frac{1}{2}\right)^3\left(\frac{1}{2}\right)^3=\frac{20}{64}

7.

有6題是非題,某生每題皆隨意作答。已知每題答對與否皆為獨立事件,求恰答對1題?

a)

C06(12)0(12)6=164C_0^6\left(\frac{1}{2}\right)^0\left(\frac{1}{2}\right)^6=\frac{1}{64}

b)

C16(12)1(12)5=664C_1^6\left(\frac{1}{2}\right)^1\left(\frac{1}{2}\right)^5=\frac{6}{64}

c)

C26(12)2(12)4=1564C_2^6\left(\frac{1}{2}\right)^2\left(\frac{1}{2}\right)^4=\frac{15}{64}

d)

C36(12)3(12)3=2064C_3^6\left(\frac{1}{2}\right)^3\left(\frac{1}{2}\right)^3=\frac{20}{64}

8.

有6題是非題,某生每題皆隨意作答。已知每題答對與否皆為獨立事件,求全答錯的機率?

a)

C06(12)0(12)6=164C_0^6\left(\frac{1}{2}\right)^0\left(\frac{1}{2}\right)^6=\frac{1}{64}

b)

C16(12)1(12)5=664C_1^6\left(\frac{1}{2}\right)^1\left(\frac{1}{2}\right)^5=\frac{6}{64}

c)

C26(12)2(12)4=1564C_2^6\left(\frac{1}{2}\right)^2\left(\frac{1}{2}\right)^4=\frac{15}{64}

d)

C36(12)3(12)3=2064C_3^6\left(\frac{1}{2}\right)^3\left(\frac{1}{2}\right)^3=\frac{20}{64}

9.

附圖是一個彈珠檯的示意圖,從上方放入一顆彈珠,假設彈珠每次滑落撞擊到釘柱時,會隨機地向右或向左落下,進而撞擊到下一層的釘柱,總共撞擊4次,最後落到下方編號0到4的格子中。已知彈珠每次撞擊後向右或向左落下的機率相等。求彈珠落到1號格子的機率

a)

C04(12)0(12)4=116C_0^4\left(\frac{1}{2}\right)^0\left(\frac{1}{2}\right)^4=\frac{1}{16}

b)

C14(12)1(12)3=416C_1^4\left(\frac{1}{2}\right)^1\left(\frac{1}{2}\right)^3=\frac{4}{16}

c)

C24(12)2(12)2=616C_2^4\left(\frac{1}{2}\right)^2\left(\frac{1}{2}\right)^2=\frac{6}{16}

d)

116+416+616=1116\frac{1}{16}+\frac{4}{16}+\frac{6}{16}=\frac{11}{16}

10.

附圖是一個彈珠檯的示意圖,從上方放入一顆彈珠,假設彈珠每次滑落撞擊到釘柱時,會隨機地向右或向左落下,進而撞擊到下一層的釘柱,總共撞擊4次,最後落到下方編號0到4的格子中。已知彈珠每次撞擊後向右或向左落下的機率相等。求彈珠落到2號格子的機率?

a)

C04(12)0(12)4=116C_0^4\left(\frac{1}{2}\right)^0\left(\frac{1}{2}\right)^4=\frac{1}{16}

b)

C14(12)1(12)3=416C_1^4\left(\frac{1}{2}\right)^1\left(\frac{1}{2}\right)^3=\frac{4}{16}

c)

C24(12)2(12)2=616C_2^4\left(\frac{1}{2}\right)^2\left(\frac{1}{2}\right)^2=\frac{6}{16}

d)

116+416+616=1116\frac{1}{16}+\frac{4}{16}+\frac{6}{16}=\frac{11}{16}

11.

附圖是一個彈珠檯的示意圖,從上方放入一顆彈珠,假設彈珠每次滑落撞擊到釘柱時,會隨機地向右或向左落下,進而撞擊到下一層的釘柱,總共撞擊4次,最後落到下方編號0到4的格子中。已知彈珠每次撞擊後向右或向左落下的機率相等。求彈珠落到0號格子的機率?

a)

C04(12)0(12)4=116C_0^4\left(\frac{1}{2}\right)^0\left(\frac{1}{2}\right)^4=\frac{1}{16}

b)

C14(12)1(12)3=416C_1^4\left(\frac{1}{2}\right)^1\left(\frac{1}{2}\right)^3=\frac{4}{16}

c)

C24(12)2(12)2=616C_2^4\left(\frac{1}{2}\right)^2\left(\frac{1}{2}\right)^2=\frac{6}{16}

d)

116+416+616=1116\frac{1}{16}+\frac{4}{16}+\frac{6}{16}=\frac{11}{16}