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Mid Unit Review 11

Total questions: 11

Worksheet time: 33mins

Name
Class
Date
1.

What is a permutation?

There may be multiple correct answers

a)

Arrangement of items where order does NOT matter

b)

Arrangement of items where order does matter

c)

nCr=n!r!(nr)!nCr=\frac{n!}{r!\left(n-r\right)!}

d)

nPr =n!(nr)!=\frac{n!}{\left(n-r\right)!}

2.

What is a combination?

There may be multiple correct answers

a)

Arrangement of items where order does NOT matter

b)

Arrangement of items where order does matter

c)

nCr=n!r!(nr)!nCr=\frac{n!}{r!\left(n-r\right)!}

d)

nPr =n!(nr)!=\frac{n!}{\left(n-r\right)!}

3.

There are 8 candidates for 2 positions. How many ways can the positions be filled?

a)

8P2=8!(82)!=56_8P_2=\frac{8!}{(8-2)!}=56

b)

8C2=8!2!(82)!=28_8C_2=\frac{8!}{2!(8-2)!}=28

c)

2P8=2!(28)!= .0027_2P_8=\frac{2!}{(2-8)!}=\ -.0027

d)

2C8=2!8!(28)!=6.9e8_2C_8=\frac{2!}{8!(2-8)!}=-6.9e^{-8}

4.

There are positions A, B, C, D open for a job and 14 candidates. In how many ways can the jobs be awarded in this order?

a)

14P4=14!(144)!=24024_{14}P_4=\frac{14!}{(14-4)!}=24024

b)

14C4=14!4!(144)!=1001_{14}C_4=\frac{14!}{4!(14-4)!}=1001

c)

4P14=4!(414)!= 0_4P_{14}=\frac{4!}{(4-14)!}=\ 0

d)

4C14=4!14!(414)!=0_4C_{14}=\frac{4!}{14!(4-14)!}=0

5.

A spinner with 6 equal sections is used.

What is the theoretical probability of spinning an odd number?

a)

1/6

b)

3/6

c)

1/3

d)

1/2

6.

A target is 24 inches by 22 inches and the center

target is 5 inches by 3 inches.

What is the probability the ball will hit the center target?

a)

846=.1739=17.4%\frac{8}{46}=.1739=17.4\%

b)

15528=.0284=2.9%\frac{15}{528}=.0284=2.9\%

c)

52815=35.2=35.2%\frac{528}{15}=35.2=35.2\%

7.

What is the probability of independent events?

a)

P(A and B)= P(A)P(B)

b)

P(A and B)= P(A) + P(B)

c)

P(A and B)= P(A) - P(B)

d)

P(A and B)= P(A)/P(B)

8.

There are 6 blue and 5 red cards in one pile and there are 7 white and 8 black cards in another pile.

What is the probability of selecting a blue and a black card?

a)

611815=48165=1655\frac{6}{11}\cdot\frac{8}{15}=\frac{48}{165}=\frac{16}{55}

b)

611+815=1426\frac{6}{11}+\frac{8}{15}=\frac{14}{26}

c)

6587=4835\frac{6}{5}\cdot\frac{8}{7}=\frac{48}{35}

9.

What is the equation for Conditional Probability?

a)

P(BA) =P(A and B)P(A)P\left(B\left|A\right|\right)\ =\frac{P\left(A\ and\ B\right)}{P\left(A\right)}

b)

P(A and B)=P(A)P(B)P\left(A\ and\ B\right)=P\left(A\right)P\left(B\right)

c)

P(A or B)=P\left(A\ or\ B\right)=

P(A)+P(B)P(A and B)P\left(A\right)+P\left(B\right)-P\left(A\ and\ B\right)

10.

A promotion has a 3% chance of awarding a prize. Suppose you have 9 cards.

What is the probability as a percent that 1 card is a winner?

a)

21.2%

b)

3%

c)

15%

d)

12.1%

11.

How ready do you feel for the exam?

a)

100%

b)

75%

c)

50%

d)

25%

e)

0%