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Double Integral

Total questions: 10

Worksheet time: 5mins

Name
Class
Date
1.

x2dydx\int\int x^2dydx  

a)

x3y3+Cx^3y^3+C  

b)

13x3y3+C\frac{1}{3}x^3y^3+C  

c)

13xy3+C\frac{1}{3}xy^3+C  

d)

13x3y+C\frac{1}{3}x^3y+C  

2.

(yz)dxdy\int\int\left(y-z\right)dxdy  

a)

12xy2xyz+C\frac{1}{2}xy^2-xyz+C  

b)

12xy2+xyz+C\frac{1}{2}xy^2+xyz+C  

c)

12x2yxyz+C\frac{1}{2}x^2y^{ }-xyz+C  

d)

12xy2x2yz+C\frac{1}{2}xy^2-x^2yz+C  

3.

(3x2+2y)dxdy\int\int\left(3x^2+2y\right)dxdy  

a)

xy(y2+x)+Cxy\left(y^2+x\right)+C  

b)

xy(x2+y)+Cxy\left(x^2+y\right)+C  

c)

x3y2+xy2+Cx^3y^2+xy^2+C  

d)

x2y3+xy+Cx^2y^3+xy+C  

4.

1234(2x7y)dxdy\int_1^2\int_3^4\left(2x-7y\right)dxdy  

a)

3.50

b)

-3.50

c)

1.50

d)

-1.50

5.

35 53 x2y2 dxdy\int_{-3}^5\ \int_5^{-3}\ x^2y^2\ dxdy  

a)

2, 567\approx-2,\ 567  

b)

1, 890\approx1,\ 890  

c)

4, 215\approx4,\ 215  

d)

1,941\approx1,941  

6.

2958 (sin 2x)dxdy\int_2^9\int_5^8\ \left(\sin\ 2x\right)dxdy  

a)

0.792\approx0.792  

b)

0.518\approx0.518  

c)

0.231\approx-0.231  

d)

0.415\approx0.415  

7.

Curves  x2=2yx^2=2-y  and  x=yx=y  are shown in this figure. Set up a double integral to find the area of the blue region.

a)

21xx21 dydx\int_{-2}^1\int_x^{x^2}1\ dydx  

b)

x2121 dydx\int_x^2\int_1^21\ dydx  

c)

21x(2x2)1 dydx\int_{-2}^1\int_x^{\left(2-x^2\right)}1\ dydx  

d)

20y(2y)1 dxdy\int_{-2}^0\int_y^{\left(2-y\right)}1\ dxdy  

8.

The base of a solid is the blue region which is a quarter of the circle  x2+y2=64x^2+y^2=64  . If the volume of the solid is given by  080mf(x,y) dydx\int_0^8\int_0^mf\left(x,y\right)\ dydx , find m.

a)

8

b)

x264\sqrt{x^2-64}  

c)

8x2\sqrt{8-x^2}  

d)

64x2\sqrt{64-x^2}  

9.

A cheese with width = 5cm, length = 10cm and height = 5cm is placed at the origin of xyz axes as shown in the figure. Set up a double integral to determine the volume of the cheese.

a)

0100y25 dxdy\int_0^{10}\int_0^{\frac{y}{2}}5\ dxdy

b)

0502x1 dydx\int_0^5\int_0^{2x}1\ dydx

c)

010055 dxdy\int_0^{10}\int_0^55\ dxdy

d)

05052x dydx\int_0^5\int_0^52x\ dydx

10.

The base of a solid is the blue region which is a quarter of the circle  x2+y2=64x^2+y^2=64  . If the volume of the solid is given by  080mf(x,y) dydx\int_0^8\int_0^mf\left(x,y\right)\ dydx , find m.

a)

8

b)

x264\sqrt{x^2-64}  

c)

8x2\sqrt{8-x^2}  

d)

64x2\sqrt{64-x^2}