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WorksheetsQuiz 4.1
Total questions: 20
Worksheet time: 15mins
price = 49
txt = "The price is {} dollars"
print(txt.format(price))
what is output ??
(a)
import numpy as np
arr = np.array([1, 2, 3, 4, 5])
print(arr)
(1 2 3 4 5)
[1 2 3 4 5]
1 2 3 4 5
{1 2 3 4 5}
import numpy as np
arr = np.array([1, 2, 3, 4, 5])
print(arr)
print(type(arr))
array
tuple
list
all choices is wrong
import numpy as np
d = np.array([[[1, 2, 3], [4, 5, 6]], [[1, 2, 3], [4, 5, 6]]])
print(d.ndim)
(a)
import numpy as np
arr = np.array([[[1, 2, 3], [4, 5, 6]], [[7, 8, 9], [10, 11, 12]]])
print(arr[-1, 0, -2])
(a)
import numpy as np
arr = np.array([[1,2,3,4,5], [6,7,8,9,10]])
print(arr[-2, -5] arr[0, 0] arr[1, 1])
(a)
import numpy as np
arr = np.array([1, 2, 3, 4, 5, 6, 7])
print(arr[3:5])
[3 4 5]
[3:5]
[4,5]
all choices is wrong
import numpy as np
arr = np.array([[1, 2, 3, 4, 5], [6, 7, 8, 9, 10]])
print(arr[0:1, 1:-2])
[]
[[2 3],[7 8]]
[[2 3]]
all choices is wrong
import numpy as np
arr = np.array([1, 2, 3, 4], dtype='i4')
print(arr)
(a)
import numpy as np
arr = np.array([1.1, 2.1, 3.1])
newarr = arr.astype('S')
print(newarr)
print(newarr.dtype)
[1.1' 2.1' 3.1']
|S32
[b'1.1' b'2.1' b'3.1']
|float64
[b'1.1' b'2.1' b'3.1'] |S32
[1.1' 2.1' 3.1']
|float64
import numpy as np
arr = np.array([-1,1,0,-3,3,0])
newarr = arr.astype(bool)
print(newarr) print(newarr.dtype)
[ True True False True True False]
bool
[ False True False False True False]
bool
ERROR
all choices is wrong
import numpy as np
arr = np.array([1, 2, 3, 4, 5])
x = arr.view()
x[0] = 31
print(arr)
print(x)
[31 2 3 4 5]
[1 2 3 4 5]
[1 2 3 4 5]
[1 2 3 4 5]
[1 2 3 4 5]
[31 2 3 4 5]
[31 2 3 4 5]
[31 2 3 4 5]
import numpy as np
arr = np.array([[1, 2, 3, 4], [5, 6, 7, 8]])
print(arr.shape)
(a)
import numpy as np
arr = np.array([1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12])
I want to make newarr with same elements in new size (2,3,2)
write function to make newarr ???
(a)
import numpy as np
arr1 = np.array([1, 2, 3])
arr2 = np.array([4, 5, 6])
arr = np.stack((arr1, arr2), axis=1)
print(arr)
[[1 4] [2 5] [3 6]]
[1 2 3 4 5 6]
[[1 2 3] [4 5 6]]
[4 5 6]
import numpy as np
arr1 = np.array([1, 2, 3])
arr2 = np.array([4, 5, 6])
arr = np.dstack((arr1, arr2))
print(arr)
[[1 2 3] [4 5 6]]
[1 2 3 4 5 6]
[[[1 4] [2 5] [3 6]]]
[4 5 6]
import numpy as np
arr1 = np.array([1, 2, 3])
arr2 = np.array([4, 5, 6])
arr = np.vstack((arr1, arr2))
print(arr)
[[[1 4] [2 5] [3 6]]]
[4 5 6]
[1 2 3 4 5 6]
[[1 2 3] [4 5 6]]
import numpy as np
arr1 = np.array([1, 2, 3])
arr2 = np.array([4, 5, 6])
arr = np.hstack((arr1, arr2))
print(arr)
(a)
class Home:
def init(self,name,HomeName):
self.name=name
self.HomeName=HomeName
x = Home("Ahmed","Giza")
print(x.HomeName)
(a)
import datetime
x = datetime.datetime.now()
print(x.month)(a)
