Free Printable Topic 1: Chi-Square

1.

Find the degrees of freedom.

a)

4

b)

5

c)

6

d)

7

2.

What are the expected counts of a female who likes Pepsi?

a)

10.5

b)

11

c)

14.5

d)

6.3

3.

All current-carrying wires produce electro-magnetic (EM) radiation. High-frequency EM radiation is thought to be a cause of cancer. The lower frequencies are generally assumed to be harmless. To investigate the relationship between current configuration and type of cancer, researchers visited the addresses of a random sample of children who died of some form of cancer (leukemia, lymphoma, or some other type) and classified the wiring configuration outside the dwelling as either high-current configuration (HCC) or low-current configuration (LCC). The data is provided in a table. Which of the following may we conclude, based on the test results?

a)

There is convincing evidence of an association between wiring configuration and the chance that a child will develop some form of cancer.

b)

HCC either causes cancer directly or is a major contributing factor to the development of cancer in children.

c)

There is not convincing evidence of an association between wiring configuration and the type of cancer that cause the deaths of children in the study.

d)

There is convincing evidence that HCC does not cause cancer in children.

4.

What is the

χ²_calculatedvaluefor the following situation to 3 sig figs?

(a)

5.

If the χ²_criticalvalue= 5.99 and the

χ²_calculatedvalue = 7.35, what is the conclusion

a)

Reject Ho, accept H1

b)

Accept Ho, reject H1

c)

there is not enough info to decide

d)

The conclusion can only be made if we also know the p-value

6.

What is the null hypothesis?

a)

Injury type is independent of position played

b)

Injury type is dependent on the position played independent

c)

Injury type is correlated to position played.

7.

What are the degrees of freedom for the following χ² test?

a)

6

b)

2

c)

5

d)

12

8.

If we are testing at a 5% significance level and our p-value is 0.00453, what is the conclusion?

a)

Accept Ho

b)

Reject Ho

c)

We need to know chi-squared

d)

You cannot do this problem without a calculator

9.

What type of test?

Is the type of television show that a person chooses to watch related to the brand of deodorant that a person uses? 1500 people were surveyed.

a)

Chi-square Goodness of Fit Test

b)

Chi-Square Test for Independence

c)

Chi-squared test for correlation

d)

Not a Chi-square test

10.

10. Which of the following is an appropriate null hypothesis for a chi-squared test for independence?

a)

There is no association between variable X and variable Y in our given population.

b)

There is an association between the two variables we are measuring.

c)

We have evidence of the two variables being connected

d)

p1=0

11.

12. How do we determine the degrees of freedom for a chi square test with two variables (homogeneity or independence)?

a)

(number of rows-1)(number of columns-1)

b)

Number of columns minus 1

c)

Number of Rows minus 1

d)

Table total minus 1

12.

14. A random sample is taken between high school students on what their favorite type of cheese is and if they like cake or pie. Which chi-squared test would be appropriate here to determine if cheese and dessert preference are associated?

a)

Chi Squared Test for Independence

b)

Chi Squared Test for Homogeneity

c)

Chi Squared Test for Difference of Squares

d)

Chi Squared Goodness of Fit Test

13.

All current-carrying wires produce electromagnetic (EM) radiation, including the electrical wiring running into, through, and out of our homes. High-frequency EM radiation is thought to be a cause of cancer. The lower frequencies associated with household current are generally assumed to be harmless. To investigate the relationship between current configuration and type of cancer, researchers visited the addresses of a random sample of children who had died of some form of cancer (leukemia, lymphoma, or some other type) and classified the wiring configuration outside the dwelling as either a high-current configuration (HCC) or a low-current configuration (LCC). Computer software was used to analyze the data.

The $\chi^2$ statistic rounded to 3 sig figs is:

(a)

14.

All current-carrying wires produce electromagnetic (EM) radiation, including the electrical wiring running into, through, and out of our homes. High-frequency EM radiation is thought to be a cause of cancer. The lower frequencies associated with household current are generally assumed to be harmless. To investigate the relationship between current configuration and type of cancer, researchers visited the addresses of a random sample of children who had died of some form of cancer (leukemia, lymphoma, or some other type) and classified the wiring configuration outside the dwelling as either a high-current configuration (HCC) or a low-current configuration (LCC). Computer software was used to analyze the data.

The expected count for HCC and Lymphoma rounded to 3 sig figs is:

(a)

15.

The degrees of freedom for the chi-square test for this two-way table are

a)

4

b)

8

c)

10

d)

20

e)

4876

16.

The expected count of females who respond "almost certain" to 4 sig figs is:

(a)

17.

The expected count of males who respond "A good chance" to 4 sig figs is:

(a)

18.

The Χ² value to 3 sig figs is:

(a)

19.

Find the chi-squared calculated value for the table. (3 sig figs)

(a)

Topic 1: Chi-Square

Total questions: 19

Worksheet time: 20mins

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