Free Printable Chi Squared Test for Independence Quiz

1.

What is the formula for calculating degrees of freedom in a chi squared test?

a)

(r-1)(c-1)

b)

r/c

c)

r+c

d)

r*c

2.

How do you interpret critical values in a chi squared test?

a)

Critical values have no significance in a chi squared test

b)

Critical values are used to determine the expected data from the observed data

c)

The null hypothesis is rejected if the calculated chi squared value is less than the critical value

d)

If the calculated chi squared value is greater than the critical value, then the null hypothesis is rejected.

3.

What are the steps involved in performing a test of independence using a chi squared table?

a)

2. Use the t-test to compare the groups.

b)

3. Look up the p-value in the chi-squared table.

c)

1. State the null and alternative hypotheses. 2. Calculate the expected frequencies for each cell. 3. Calculate the chi-squared test statistic. 4. Determine the degrees of freedom. 5. Look up the critical value in the chi-squared table. 6. Compare the calculated chi-squared value with the critical value. 7. Make a decision about the null hypothesis.

d)

1. Calculate the mean and median of the data.

4.

Explain the concept of expected frequencies in the context of chi squared test.

a)

Expected frequencies are the frequencies that are randomly assigned to each category.

b)

Expected frequencies are the frequencies that are based on personal assumptions rather than statistical analysis.

c)

Expected frequencies are the frequencies that would be expected in each category if there was no relationship between the variables being studied.

d)

Expected frequencies are the frequencies that are guaranteed to occur in each category.

5.

How do you calculate the expected frequencies in a chi squared test?

a)

Multiply the row total by the column total and then divide by the grand total.

b)

Subtract the row total from the column total

c)

Add the row total to the column total

d)

Divide the row total by the column total

6.

Explain the relationship between observed and expected frequencies in a chi squared test.

a)

The observed frequencies are the actual counts of data in each category, while the expected frequencies are the counts that would be expected if the null hypothesis were true.

b)

The expected frequencies are the actual counts of data in each category

c)

The observed frequencies are always higher than the expected frequencies

d)

There is no relationship between observed and expected frequencies

7.

What are the expected counts of a female who likes Pepsi?

a)

10.5

b)

11

c)

14.5

d)

6.3

8.

What is the null hypothesis?

a)

Injury type is independent of position played

b)

Injury type is dependent on the position played independent

9.

If the χ²_criticalvalue= 5.99 and the

χ²_calculatedvalue = 7.35, what is the conclusion

a)

Reject Ho, accept H1

b)

Accept Ho, reject H1

c)

there is not enough info to decide

d)

The conclusion can only be made if we also know the p-value

10.

What are the degrees of freedom for the following χ² test?

a)

6

b)

2

c)

5

d)

12

11.

Chi-squared tests are invalid if:

a)

The Chi-square calculated is really large

b)

One of the expected values is less than 5

c)

One of the observed values is bigger than 500

d)

The Chi-square calculated is really small

12.

Find the degrees of freedom.

a)

4

b)

5

c)

6

d)

7

13.

All current-carrying wires produce electromagnetic (EM) radiation, including the electrical wiring running into, through, and out of our homes. High-frequency EM radiation is thought to be a cause of cancer. The lower frequencies associated with household current are generally assumed to be harmless. To investigate the relationship between current configuration and type of cancer, researchers visited the addresses of a random sample of children who had died of some form of cancer (leukemia, lymphoma, or some other type) and classified the wiring configuration outside the dwelling as either a high-current configuration (HCC) or a low-current configuration (LCC). Computer software was used to analyze the data.

The expected count of cases of lymphoma in homes with an HCC is

a)

$\frac{79\times31}{215}$

b)

$\frac{10\times21}{215}$

c)

$\frac{79\times31}{10}$

d)

$\frac{136\times31}{215}$

e)

None of the above

14.

All current-carrying wires produce electromagnetic (EM) radiation, including the electrical wiring running into, through, and out of our homes. High-frequency EM radiation is thought to be a cause of cancer. The lower frequencies associated with household current are generally assumed to be harmless. To investigate the relationship between current configuration and type of cancer, researchers visited the addresses of a random sample of children who had died of some form of cancer (leukemia, lymphoma, or some other type) and classified the wiring configuration outside the dwelling as either a high-current configuration (HCC) or a low-current configuration (LCC). Computer software was used to analyze the data.

The $\chi^2$ statistic is equal to;

(give your answer to 3 decimal places

(a)

15.

In the formula for Chi Sqare, the O stands for

a)

the sum

b)

the observed frequency

c)

The expected frequency

d)

the p value

Chi Squared Test for Independence Quiz

Total questions: 15

Worksheet time: 3hrs 30mins

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