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Stellar Classification

Total questions: 12

Worksheet time: 14mins

Name
Class
Date
1.

Harvard Classification Scheme from A to P class stars are based on

a)

Star's temperature

b)

Strength of Balmer lines

c)

Stellar Compositions

d)

Star's Energy

2.

Balmer lines are strongest in which class stars?

a)

O5 class stars

b)

A2 class stars

c)

G2 class stars

d)

M5 class stars

3.

What is the relation between the strength of Balmer lines and classification the classification of OBAFGKM

a)

The coolest star is Hydrogen poor has the strongest Balmer lines

b)

The hottest star is Hydrogen rich, hence the strongest Balmer lines

c)

Balmer lines is lower near the hottest star and steadily increases from O class to A class

d)

Balmer lines is strongest near the hottest star with highest Helium and Metal

4.

Equivalent Width (EW) is useful to characterize the strength of absorption lines. EW is proportional to

a)

The distance of the star

b)

The intensity of the flux density

c)

The length of missing flux

d)

Wavelength of the stars measured

5.

Boltzmann Excitation Equilibrium Equation states the

a)

Ratio of exited atoms to the other energy levels

b)

Ratio of exited ions to the other energy levels

c)

Energy of the atom in exited state

d)

Energy of the ion in exited state

6.

Boltzmann Excitation Equilibrium Equation conclude that

a)

The strength of Balmer lines is proportional to the number of Hydrogen ion in exited state, n=2

b)

The strength of Balmer lines is proportional to the number of Hydrogen atom in exited state, n=2

c)

The strength of Balmer lines is proportional to the temperature of Hydrogen atom populated

d)

The strength of Balmer lines is proportional to the temperature of Hydrogen ions populated

7.

Saha equation tells us that

a)

Strength of Balmer lines in higher temperature where the atoms is ionized

b)

ratio of the number of Hydrogen atom in higher state

to the number of atom in lower state

c)

ratio of the number of ions in higher state

to the number of ions in lower state

d)

Strength of Balmer lines at temperature 10000K where the Hydrogen atoms is completely ionized

8.

This diagram displays the rise and fall of

all non-ground state transitions with temperature. From this diagram we can deduce that

a)

series of optical stellar spectra displays the

systematic change in absorption line strengths

with temperature.

b)

smooth variation along the spectral types indicates minor variations of the chemical composition of stars with temperature.

c)

ionization occurs over a small temperature range. The Hydrogen neutral at 7000 K - 10,000 K.

d)

equivalent width is the amount

of wavelength the amount of

spectrum that would be completely “black”.

9.

Why were there not any hydrogen features in red and cooler stars?

a)

because it is late type and Hydrogen poor

b)

because it is early type and Helium rich

c)

because the Hydrogen atom is in ground state

d)

because the stars are runs out of Hydrogen

10.

Why were very minimum hydrogen features in blue and hottest stars?

a)

because it is early type, hence Hydrogen poor

b)

because all the Hydrogen is almost ionized

c)

because it early type, hence Helium rich

d)

because the Hydrogen is in the ground state

11.

The temperature of the star dependent upon the strength of Balmer lines.

a)

TRUE

b)

FALSE

12.

Very thin absorption line in high luminosity class star in Morgan-Keenan (MK) System is due to

a)

pressure broadening in high mass stars

b)

error in spectral parallax

c)

very low atom Hydrogen in exited state

d)

most of atom Hydrogen is in ionized state, therefore it can absorbs radiation