WorksheetsMath 7 Algebraic Expressions and Equations CAASPP Review
Total questions: 14
Worksheet time: 16mins
Find the value of x that satisfies the equation.
0.05+10015=100x+10015
(a)
Calculate the result of 2.5 ⋅ (8 + 4).
24
30
22
24.5
What is the result of 3.7 ⋅ (6 + 2)?
29.6
26
28
22
Sarah has saved $45. She earns $9 per hour at her job. She plans to buy a concert ticket for $180. Enter the minimum number of hours Sarah must work in order to buy the concert ticket.
5 hours
10 hours
15 hours
20 hours
John purchased 3 bags of rice and 5 loaves of bread for a total cost of $35.25. Each bag of rice costs $5.75. Enter the cost, in dollars, of 1 loaf of bread.
(a)
The 8th grade has 675 students. Two-thirds of the students are boys. How many girls are in the 8th grade?
A group of 5 coworkers each purchase 1 movie ticket and 1 medium soda at the cinema. Each ticket costs $9. The group spends a total of $60. Calculate the cost of 1 medium soda.
(a)
Samantha hires a car service to travel from her office to a client's location. The service charges a flat fee of $4.50 to book the ride, plus $3.00 for every mile traveled. If Samantha's trip costs her a total of $31.50, write an equation that represents this situation. Let m represent the number of miles to the client's location.
4.50 + 3 = 31.50
m + 4.50 = 31.50
4.50 + 3m = 31.50
4.50m + 3 = 31.50
A teacher purchases a book and a set of markers for each of the 15 students in the art class. Each set of markers costs $5.00. The teacher spends a total of $375 on both books and markers. Enter an equation that models the situation with b, the cost of 1 book.
75 - 15b = 375
75 + 15b = 375
15b = 375
75 + b = 375
Lisa is preparing a special blend of tea using dried chamomile and lavender. She bought 3 pounds of dried chamomile. She also bought some dried lavender. Dried chamomile and lavender each cost $3.50 per pound. The total amount Lisa spent on the dried chamomile and lavender was $17.50. Enter the number of pounds of dried lavender Lisa purchased.
Identify all expressions equivalent to
65⋅12÷2−2
10÷2
5−2
6⋅65−2
65⋅12÷0
Simplify the following expression
2 43⋅2+2⋅4+3⋅1
16 21
66 41
20
Level 3.
Solve the inequality. Graph the solution.
y+5 ≥ 2
7n - 1 > 76
