WorksheetsMagnetism and EMI
Total questions: 6
Worksheet time: 7mins
The diagram shows a current I in a vertical square coil.
The coil can rotate about an axis OO’.
The plane of the coil is at right angles to a uniform horizontal magnetic field of flux density B
Which statement is correct?
The forces on the vertical sides of the coil are equal in magnitude
and opposite in direction.
A non-zero couple acts on the coil.
No forces act on the horizontal sides of the coil.
The forces on all sides of the coil act toward the centre of the coil.
When an electron is moving at a speed v perpendicular to a uniform magnetic field of flux density
B, it follows a path of radius R.
A second electron moves at a double the speed and perpendicular to a uniform magnetic field of flux density 4B.
What is the radius of the path of the second electron?
R/8
R/2
2R
8R
Three identical magnets P, Q and R are released simultaneously from rest and fall to the ground
from the same height.
P falls directly to the ground.
Q falls through the centre of a thick horizontal conducting ring.
R falls through a similar ring that has a gap cut into it.
P and R arrive together, followed by Q.
P and Q arrive together, followed by R.
P arrives first, followed by Q which is followed by R.
All three magnets arrive simultaneously.
Different magnetic fields are present in the two chambers shown. A particle enters the first
chamber at a velocity of 80 m s–1 and is deflected into a circular path of radius 200 mm
In the second chamber it follows a circular path of radius 100 mm
The particle leaves the second chamber at a speed of
20m/s
40m/s
80m/s
160m/s
A current-carrying conductor with length l is placed at right angles to a magnetic field with
magnetic flux density B. The graph shows how the force on the wire varies with the current
passing through it.
B
Bl
L/B
B/L
The beam is produced by accelerating electrons through a potential difference of 250 V.
The electric field strength is 1.4 × 10*4 V m−1. The magnetic flux density is
1.5 × 10*−3T.
A uniform electric field of electric field
strength E is applied given that the electric and magnetic forces on the electrons are equal and
in opposite directions. Calculate the value of the charge/ mass (e/m) for the electron using this data.
1.7x10*21C/kg
2.7x10*11C/kg
1.7x10*11C/kg
1.7x10*-11C/kg
