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WorksheetsSeries Circuits Quiz
Total questions: 19
Worksheet time: 34mins
What is the total resistance in a series circuit with three resistors of 2 ohms, 3 ohms, and 5 ohms?
10 ohms
9 ohms
5 ohms
15 ohms
In a series circuit, if the voltage across the battery is 12V and the total resistance is 4 ohms, what is the current flowing through the circuit?
48 A
3 A
0.33 A
8 A
If one of the bulbs in a series circuit burns out, what happens to the current in the circuit?
It increases.
It decreases.
It remains the same.
The circuit stops conducting.
What is the voltage across a resistor of 2 ohms when a current of 2 A flows through it?
1 V
4 V
2 V
0.5 V
A series circuit with a 4 Ω resistor and two 1 Ω resistors has a current of 2 A. What is the total voltage across the circuit?
3 V
12 V
6 V
8 V
How does adding more resistors in a series circuit affect the total resistance?
It decreases.
It remains the same.
It increases.
It first increases, then decreases.
What is the equivalent resistance in a series circuit if there are four resistors connected in series, each of 4 ohms?
4 ohms
8 ohms
16 ohms
12 ohms
In a series circuit, if the total voltage is 20V and the resistance is 5 ohms, what is the power dissipated in the circuit?
80 W
4 W
20 W
40 W
If a series circuit consists of a 6V battery and two resistors of 2 ohms and 3 ohms, what is the current flowing through the circuit?
1.2 A
2 A
0.5 A
1 A
What happens to the total voltage in a series circuit when more batteries are added?
It decreases.
It remains the same.
It increases.
It first increases, then decreases.
What happens to the total resistance in a series circuit when more resistors are added?
It increases
It decreases
It remains the same
It becomes zero
What happens to the total current in a series circuit when more resistors are added?
It increases
It decreases
It remains the same
It becomes zero
In a series circuit, if one component fails, what happens to the flow of electricity?
It continues through other paths
It stops completely
It doubles
It halves
What is the formula for calculating the total resistance in a series circuit?
Rtotal=R11+R21+...+Rn1
Rtotal=R1+R2+...+Rn
Rtotal=R1+R2+...+RnR1×R2×...×Rn
Rtotal=R12+R22+...+Rn2
In a series circuit:
R1 = 6 Ω
R2 = 10 Ω
R3 = 5 Ω
and a light bulb has a resistance of 3Ω.
If the total voltage in the circuit is 48 V, what is the current through the light bulb?
In a series circuit:
R1 = 6 Ω
R2 = 10 Ω
R3 = 5 Ω
and a light bulb has a resistance of 3Ω.
If the total voltage in the circuit is 48 V, what is the voltage drop through the light bulb?
In a series circuit:
R1 = 6 Ω
R2 = 10 Ω
R3 = 5 Ω
and a light bulb has a resistance of 3Ω.
If the total voltage in the circuit is 48 V, what is the power output of the light bulb?
Three resistors are connected in series. What we know is given in the picture.
Drag and drop to fill in what you can!
R1 = (a) R3 = (b)
V 2 = (c) V3= (d)
P2 = (e)
