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CACYOFUI PHY 101 QUIZ

Total questions: 10

Worksheet time: 10mins

Name
Class
Date
1.

If the position of a vector is given by x = 10 + 10t -4t 2 , where x is in meters and t is in seconds,

when is the particle’s velocity zero?

a)

10.00s

b)

2.75s

c)

C) 2.50s

d)

1.25s

2.

In equation x = ut +½at², x represents position, u is initial velocity, t is time and a is acceleration.

What will it be second derivative of x with respect to t?

a)

Final velocity

b)

Acceleration

c)

Deceleration

d)

Speed

3.

Given three vectors A = –i –4j +2k, B = 3i +2j –2k and C = 2i –3j +k Calculate A•(B×C) A) –6 B) +6

C) –4i –7j –13k D) -i –4j +2k

a)

-6

b)

+6

c)

–4i –7j –13k

d)

-i –4j +2k

4.

A vector has a magnitude of 16 units. Its x– component is 8 units. Calculate its y– component

and angle the vector makes with the x–axis respectively.

a)

13.86 units and 30⁰

b)

13.86 units and 60⁰

c)

11.54 units and 60⁰

d)

13.86 units and 45⁰

5.

In the equation Vⁿ= 2ax, the unit of variables v, a and x are m/s , m/s² and m respectively. If n is an integer, what must be the value of n that will validate the given equation?

a)

2

b)

-2

c)

1

d)

-1

6.

An object starts from rest at the origin and moves along the x axis with a constant acceleration of 4 m/s2. Its average velocity as it goes from x = 2 m to x = 8 m is: A) 1 m/s B) 2 m/s C) 3 m/s D) 5 m/s E) 6 m/s

a)

1 m/s

b)

2 m/s

c)

3 m/s

d)

5 m/s

e)

6 m/s

7.

Over a short interval near time t = 0 the coordinate of an automobile in meters is given by x(t) = 27t − 4.0t 3, where t is in seconds. At the end of 1.0 s the acceleration of the auto is:

a)

27 m/s²

b)

4.0 m/s²

c)
  • -4.0 m/s²

d)

-12m/s²

e)

-24 m/s²

8.

How far does a car travel in 6 s if its initial velocity is 2 m/s and its acceleration is 2 m/s2 in the forward direction?

a)

12m

b)

14m

c)

24m

d)

36m

e)

48m

9.

The angle between An = (25 m)ˆi + (45 m)ˆj and the positive x axis is:

a)

29°

b)

61°

c)

151°

d)

209°

e)

241°

10.

If An = (2 m)ˆi − (3 m)ˆj and Bn = (1 m)ˆi − (2 m)ˆj, then An − 2Bn =

a)

(1 m)ˆj

b)

(4 m)ˆi − (7 m)ˆj

c)

(−1 m)ˆj

d)

(4 m)ˆi + (1 m)ˆj

e)

(−4 m)ˆi + (7 m)ˆj