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QUIZ 2 DBM30043Sesi 2 23/24

Total questions: 14

Worksheet time: 30mins

Name
Class
Date
1.

CLO 1, C1

  1. 1. By using the Laplace Transform Table, find the Inverse Laplace Transform for f(t)=e2t−3tf(t)=e^{2t}-3t

a)

F(s)=1s−2−3s2F(s)=\frac{1}{s-2}-\frac{3}{s^2}

b)

F(s)=1s+2−3s2F(s)=\frac{1}{s+2}-\frac{3}{s^2}

c)

F(s)=1s−2−3sF(s)=\frac{1}{s-2}-\frac{3}{s}

d)

F(s)=1s+2−3sF(s)=\frac{1}{s+2}-\frac{3}{s}

2.

CLO 1, C1

  1. 2. By using the Laplace Transform Table, find the Inverse Laplace Transform for f(t)=e4t3f(t)=\frac{e^{4t}}{3}

a)

F(s)=13s−12F(s)=\frac{1}{3s-12}

b)

F(s)=13s+12F(s)=\frac{1}{3s+12}

c)

F(s)=3s−4F(s)=\frac{3}{s-4}

d)

F(s)=3s+4F(s)=\frac{3}{s+4}

3.

CLO 1, C2

  1. 3. By using the Laplace Transform Table, find the Inverse Laplace Transform for f(t)=2e−4tsin⁡⁡tf(t)=2e^{-4t}\sin⁡t

a)

F(s)=2(s+4)2+1F(s)=\frac{2}{(s+4)^2+1}

b)

F(s)=1(s+4)2+2F(s)=\frac{1}{(s+4)^2+2}

c)

F(s)=2(s+1)2+4F(s)=\frac{2}{(s+1)^2+4}

d)

F(s)=2(s−1)2+4F(s)=\frac{2}{(s-1)^2+4}

4.

CLO 1, C2

  1. 4. By using the Laplace Transform Table, find the Laplace Transform for f(t)=3(sin⁡⁡4t+t3)f(t)=3(\sin⁡4t+t^3)

a)

F(s)=12s2+16+18s4F(s)=\frac{12}{s^2+16}+\frac{18}{s^4}

b)

F(s)=12s2+16+6s4F(s)=\frac{12}{s^2+16}+\frac{6}{s^4}

c)

F(s)=12s2−16+18s4F(s)=\frac{12}{s^2-16}+\frac{18}{s^4}

d)

F(s)=12s2−16+6s4F(s)=\frac{12}{s^2-16}+\frac{6}{s^4}

5.

CLO 1, C2

  1. 5. By using the Laplace Transform Table, find the Laplace Transform for F(s)=5ss2−25+5s−2F(s)=\frac{5s}{s^2-25}+\frac{5}{s-2}

a)

f(t)=5cosh⁡⁡5t+5e2tf(t)=5\cosh⁡5t+5e^{2t}

b)

f(t)=5cosh⁡⁡5t+5e−2tf(t)=5\cosh⁡5t+5e^{-2t}

c)

f(t)=5cosh⁡⁡25t+5e−2tf(t)=5\cosh⁡25t+5e^{-2t}

d)

f(t)=5cosh⁡⁡25t+5e2tf(t)=5\cosh⁡25t+5e^{2t}

6.

CLO 1, C3

  1. 6. By using the Laplace Transform Table, find the Laplace Transform for F(s)=4+2ss2−4F(s)=\frac{4+2s}{s^2-4}

a)

f(t)=2sinh⁡⁡2t+2cosh⁡⁡2tf(t)=2\sinh⁡2t+2\cosh⁡2t

b)

f(t)=sinh⁡⁡4t+2cosh⁡⁡4tf(t)=\sinh⁡4t+2\cosh⁡4t

c)

f(t)=4sinh⁡⁡2t+2cosh⁡⁡2tf(t)=4\sinh⁡2t+2\cosh⁡2t

d)

f(t)=2sin⁡⁡2t+2cos⁡⁡2tf(t)=2\sin⁡2t+2\cos⁡2t

7.

  1. CLO 1, C3

  2. 7. By using the Laplace Transform Table, find the Laplace Transform for F(s)=1(s+2)2+4F(s)=\frac{1}{(s+2)^2+4}

a)

f(t)=12e−2tsin⁡⁡2tf(t)=\frac{1}{2}e^{-2t}\sin⁡2t

b)

f(t)=e−2tsin⁡⁡2tf(t)=e^{-2t}\sin⁡2t

c)

f(t)=e−2tsin⁡⁡4tf(t)=e^{-2t}\sin⁡4t

d)

f(t)=14e−2tsin⁡⁡4tf(t)=\frac{1}{4}e^{-2t}\sin⁡4t

8.

 CLO 1, C1

1.     By using the Laplace Transform Table, find the Laplace Transform for f(t)=5−sin⁡3tf(t)=5-\sin3t

a)

F(s)=5s−3(s2+9)F(s)=\frac{5}{s}-\frac{3}{(s^2+9)}

b)

F(s)=5−3(s2+9)F(s)=5-\frac{3}{(s^2+9)}

c)

F(s)=5s−s(s2+9)F(s)=\frac{5}{s}-\frac{s}{(s^2+9)}

d)

F(s)=5s−3(s2+3)F(s)=\frac{5}{s}-\frac{3}{(s^2+3)}

9.

  1. CLO 1,C1

  2. 2. By using the Laplace Transform Table, find the Laplace Transform for f(t)=t33f(t)=\frac{t^3}{3}

a)

F(s)=2s4F(s)=\frac{2}{s^4}

b)

F(s)=2s3F(s)=\frac{2}{s^3}

c)

F(s)=6s4F(s)=\frac{6}{s^4}

d)

F(s)=1s4F(s)=\frac{1}{s^4}

10.

  1. CLO 1, C2

  2. 3. By using the Laplace Transform Table, find the Laplace Transform for f(t)=5e3tcos⁡4tf(t)=5e^3t\cos4t

a)

F(s)=(5s−15)((s−3)2+16)F(s)=\frac{(5s-15)}{((s-3)^2+16)}

b)

F(s)=4((s−3)2+16)F(s)=\frac{4}{((s-3)^2+16)}

c)

F(s)=(5s+15)((s+3)2+16)F(s)=\frac{(5s+15)}{((s+3)^2+16)}

d)

F(s)=(5s+15)((s+3)2+4)F(s)=\frac{(5s+15)}{((s+3)^2+4)}

11.

  1. CLO 1, C2

  2. 4.  By using the Laplace Transform Table, find the Laplace Transform for f(t)=2(sinh⁡5t−3t)f(t)=2(\sinh5t-3t)

a)

F(s)=10(s2−25)−6s2F(s)=\frac{10}{(s^2-25)}-\frac{6}{s^2}

b)

F(s)=10(s2+25)−6s2F(s)=\frac{10}{(s^2+25)}-\frac{6}{s^2}

c)

F(s)=s(s2−25)−3s2F(s)=\frac{s}{(s^2-25)}-\frac{3}{s^2}

d)

F(s)=10(s2−25)−3sF(s)=\frac{10}{(s^2-25)}-\frac{3}{s}

12.

CLO 1, C2

  1. 5. By using the Laplace Transform Table, find the Inverse Laplace Transform for F(s)=3s(s2+9)+5(s+3)F(s)=\frac{3s}{(s^2+9)}+\frac{5}{(s+3)}

a)

f(t)=3cos⁡⁡3t+5e−3tf(t)=3\cos⁡3t+5e^{-3t}

b)

f(t)=3cos⁡⁡9t+5e−3tf(t)=3\cos⁡9t+5e^{-3t}

c)

f(t)=3cos⁡⁡3t+5e3tf(t)=3\cos⁡3t+5e^{3t}

d)

f(t)=3sin⁡⁡3t+5e−3tf(t)=3\sin⁡3t+5e^{-3t}

13.

  1. CLO 1, C3

  2. 6. By using the Laplace Transform Table, find the Inverse Laplace Transform for F(s)=1s4+5(s2+4)F(s)=\frac{1}{s^4}+\frac{5}{(s^2+4)}

a)

f(t)=16t3+52sin⁡⁡2tf(t)=\frac{1}{6}t^3+\frac{5}{2}\sin⁡2t

b)

f(t)=13t3+52sin⁡⁡2tf(t)=\frac{1}{3}t^3+\frac{5}{2}\sin⁡2t

c)

f(t)=16t3+5sin⁡⁡2tf(t)=\frac{1}{6}t^3+5\sin⁡2t

d)

f(t)=13t3+52sin⁡⁡2tf(t)=\frac{1}{3}t^3+\frac{5}{2}\sin⁡2t

14.

CLO 1, C3

  1. 7. By using the Laplace Transform Table, find the Inverse Laplace Transform for F(s)=10((s−4)2+25)F(s)=\frac{10}{((s-4)^2+25)}

a)

f(t)=2e4tsin⁡⁡5tf(t)=2e^{4t}\sin⁡5t

b)

f(t)=2e−4tsin⁡⁡5tf(t)=2e^{-4t}\sin⁡5t

c)

f(t)=5e4tsin⁡⁡5tf(t)=5e^{4t}\sin⁡5t

d)

f(t)=5e−4tsin⁡⁡5tf(t)=5e^{-4t}\sin⁡5t

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