Free Printable ENERGY CONVERSIONS:Formula for Energy Transformations

1.

The formula for calculating gravitational potential energy is

$GPE=m\times g\times h$

So, to calculate the mass of the object, we would use the formula

a)

$m=\frac{GPE}{g\times h}$

b)

$m=\frac{GPE\times h}{g}$

c)

$m=\frac{GPE\times g}{h}$

d)

$m=\frac{g\times h}{GPE}$

2.

The formula for calculating gravitational potential energy is

$GPE=m\times g\times h$

So, to calculate the height of the object, we would use the formula

a)

$h=\frac{GPE}{m\times g}$

b)

$h=\frac{GPE\times m}{g}$

c)

$h=\frac{GPE\times g}{m}$

d)

$h=\frac{m\times g}{GPE}$

3.

The formula for calculating the kinetic energy of an object is

$KE=\frac{1}{2}mv^2$

The formula for the mass of a moving object is

a)

$m=\frac{\frac{1}{2}KE}{v^2}$

b)

$m=\frac{2KE}{v^2}$

c)

$m=\frac{KE}{2v^2}$

d)

$m=\frac{KE}{\frac{1}{4}v^2}$

4.

The formula for calculating the kinetic energy of an object is

$KE=\frac{1}{2}mv^2$

The formula for the speed (v) of a moving object is

a)

$v=\frac{\frac{1}{2}KE}{m}$

b)

$v=\frac{2KE}{m}$

c)

$v=\frac{KE^2}{m^2}$

d)

$v=\sqrt[]{\frac{2KE}{m}}$

5.

The common factor for calculating BOTH KE and GPE is:

a)

the effect of gravity (g) on the object

b)

the mass (m) of the object

c)

The speed (v) of the object

6.

The amount of work done can be calculated using the formula.

W = Fd

The size of the force needed to move an object is calculated using the formula:

a)

$F=Wd$

b)

$F=\frac{W}{d}$

c)

$F=\frac{d}{W}$

d)

$F=\frac{1}{Wd}$

7.

The amount of work done can be calculated using the formula.

$W=Fd$

The distance (d) an object moves is calculated using the formula:

a)

$d=WF$

b)

$d=\frac{W}{F}$

c)

$d=\frac{F}{W}$

d)

$d=\frac{1}{WF}$

8.

Work and Gravitational Potential Energy are related in that:

a)

work is always done when an object is lifted or falls

b)

the amount of work done = the change in GPE

c)

work is only done if an object is raised from the ground

d)

work is not done when an object falls to the ground

9.

If the work done by an object is equal to the change in the potential energy of the object AND

$W=Fd\$ and $GPE=mgh$ then won't $Fd=mgh$

The Force involved would be calculated using the formula

a)

$F=\frac{d}{mgh}$

b)

$F=\frac{mgh}{d}$

c)

$F=\frac{mgd}{h}$

d)

$F=\frac{hg}{dm}$

10.

If the work done by an object is equal to the change in the potential energy of the object AND

$W=Fd$ and $GPE=mgh$ then won't $Fd=mgh$

The mass of the object involved can be calculated using the formula

a)

$m=\frac{d}{Fgh}$

b)

$m=\frac{gh}{Fd}$

c)

$m=\frac{Fd}{gh}$

d)

$m=\frac{hg}{dF}$

11.

Work and Kinetic Energy are related in that:

a)

work is always done when an object slows down

b)

the amount of work done = the change in KE

c)

work is only done if an object speeds up

d)

work is not done when an object slows down

12.

If the work done by an object is equal to the change in the kinetic energy of the object AND

$W=Fd$ and $KE=\frac{1}{2}mv^2$ then won't $Fd=\frac{1}{2}mv^2$

The mass of the object involved can be calculated using the formula:

a)

$m=\frac{\frac{1}{2}Fd}{v^2}$

b)

$m=\frac{2Fd}{v^2}$

c)

$m=\sqrt{\frac{\frac{1}{2}Fd}{v^2}}$

d)

$m=\sqrt{\frac{2Fd}{v^2}}$

13.

If the work done by an object is equal to the change in the kinetic energy of the object AND

$W=Fd$ and $KE=\frac{1}{2}mv^2$ then won't $Fd=\frac{1}{2}mv^2$

The speed (V) of the object involved can be calculated using the formula:

a)

$v=\frac{\frac{1}{2}Fd}{m}$

b)

$v=\frac{2Fd}{m^2}$

c)

$v=\sqrt{\frac{\frac{1}{2}Fd}{m}}$

d)

$v=\sqrt{\frac{2Fd}{m}}$

ENERGY CONVERSIONS:Formula for Energy Transformations - GPE & KE

Total questions: 13

Worksheet time: 10mins

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