WorksheetsCh. 2.3 Unbalanced Forces and Motion Test
Total questions: 18
Worksheet time: 9mins
When one object exerts a force on a second object, the second object exerts an equal force in the opposite direction on the first object is Newton's
First Law of Motion
Second Law of Motion
Third Law of Motion
Fourth Law of Motion
The acceleration of an object equals the net force divided by the object's mass is Newton's
First Law of Motion
Second Law of Motion
Third Law of Motion
Fourth Law of Motion
In a circular motion, a force that acts perpendicular to the direction of motion toward the center of the circle is
net force
gravitational force
mass
centripetal force
When a resting object is acted on by an unbalanced force, the object will ___________ in the direction of the unbalanced force.
accelerate
decelerate
An object's speed will __________ when a net force acts in the same direction as the object's motion.
oscillate
increase (speed up)
An object's speed will __________ when a net force acts in the opposite direction of the object's motion.
A ball tied to a string and swung in a circle is an example of a/an ______________.
In Newton's Second Law of Motion
a= s/f
a=F/m
F=m/a
a=Fm2
In Newton's Second Law of Motion, acceleration is measured in
meters/second2 (m/s2)
meters/second (m/s)
inches/second (in./s)
kilometers/second2 (km/s2)
Force is measured in
Inches
meters
kilograms
Newtons
Mass in Newton's Second Law of Motion is measured in
When the net force is not zero, the velocity of the object ____________.
According to the Second Law of Motion, the unbalanced/gravitational force acting on the Earth and the planets exerted by the Sun is called
centripetal force
The forces two objects exert on each other are called
force doubles
force pairs
For every action force there is a _________ force that is equal in size, but __________ in direction.
Solve for acceleration. You throw a 0.5kg basketball with a force of 20N. What is the ball's acceleration? (Use: a=F/m)
a=10m/s2
a=20m/s2
30m/s2
40m/s2
Calculate the acceleration of a 60kg sprinter if the force on the sprinter is 120N. (Use: a= F/m).
a= 1m/s2
a= 2m/s2
a= 10m/s2
a= 20m/s2
A car has a mass of 1500 kg and an acceleration of 2.0m/s2. What is the net force acting on the car?
(Use: F= ma)
1000N
2000N
3000N
4000N
