WorksheetsRedox
Total questions: 20
Worksheet time: 40mins
What is the oxidation number of chlorine in HClO?
0
-1
+1
+5
Oxidation is the _________ of electrons.
loss
gain
sharing
transfer
Reduction is the ___________ of electrons.
loss
gain
sharing
transfer
What is the oxidation number of N2?
-3
0
+4
-1
In the reaction Zn + 2HCl --> ZnCl2 + H2
which element is oxidized?
Zinc
Hydrogen
Chlorine
None
In the reaction: 2 Ca + O2 --> 2 CaO
calcium is __________
Mg → Mg2+ + 2e–
Mg loses 2 electrons
Mg stays the same
Mg gains 1 electrons
4Fe + 3O2 --> 2Fe2O3
In the reaction: Zn + Cu2+ → Zn2+ + Cu,
the Cu2+
is reduced
is oxidized
In a redox reaction, the reducing agent will
lose an electron and be reduced
lose an electron and be oxidized
gain an electron and be reduced
gain an electron and be oxidized
In the reaction: 2 Mg + O2 → 2 MgO,
the magnesium is the
oxidizing agent and is reduced
oxidizing agent and is oxidized
reducing agent and is reduced
reducing agent and is oxidized
Given the reaction: Ca + CuS → CaS + Cu,
What is the correct reduction half-reaction?
Cu+2 + 2e-1 → Cu0
Cu+2 → Cu0 + 2e-1
Cu0 + 2e-1 → Cu+2
Cu0 → Cu+2 + 2e-1
which element, if any, is oxidized?
Substance that is reduced is called the...
reducing agent
oxidation number
combustion
oxidizing agent
Substance that reduces another substance by losing electrons.
reducing agent
half-reaction
electronegative atom
oxidizing agent
What is a half-reaction of this equation, Na + Cl --> NaCl ?
Cl° + e-1 --> Cl-1
Cl° - e-1 --> Cl-1
Na+1 --> Na° + e-1
Na° + Cl°--> Na+1Cl-1
Oxidation states for
CaCrO4
Ca=+2, Cr=+6, O=-2
Ca=+2, Cr=+4, O=-2
Ca=+2, Cr=+6, O=-8
Ca=+4, Cr=+6, O=-2
Which is oxidized and which is reduced?
Ca + Na2O → Na + CaO
Oxidized: Na
Reduced: O
Oxidized: Ca
Reduced: O
Oxidized: Na
Reduced: Ca
Oxidized: Ca
Reduced: Na
Which is oxidized and which is reduced?
CaCl2 + O2 → CaClO3
Oxidized: Ca
Reduced: O
Oxidized: Cl
Reduced: O
Oxidized: Ca
Reduced: Cl
Oxidized: O
Reduced: Cl
What is a correct half reaction for the following reaction:
2 Al + N2 ----> 2 AlN
Al0 + 3 e- --> Al+3
N0 --> N+2 + 2 e-1
Al+3 + 3 e-1 --> Al0
N0 + 3 e-1 --> N-3
