$$\left(-\infty;-3\right)\cup\left(-3;\ 0\right)\cup\left(0;+\infty\right)$$

$$\left(-\infty;\ 2\right)\cup\left(2;\ +\infty\right)$$

$$\left(-\infty;\ 0\right)\cup\left(0;\ 2\right)\cup\left(2;\ +\infty\right)$$

$$\left(-\infty;\ -3\right)\cup\left(-3;\ +\infty\right)$$

$$\frac{1}{4x}$$

x/4

x+1

1/4

$$\frac{x+1}{x-1}$$

$$\frac{1}{x-3}$$

$$\frac{1}{x-1}$$

$$\frac{4x}{4x^2+3}$$

5x-1

$$25x^2-1$$

5x+1

1

$$\frac{4x-1}{3-8x}$$

$$\frac{8x+1}{8x-3}$$

$$\frac{-8x-1}{3-8x}$$

1

$$\frac{18-x}{x+2}$$

 $$\frac{20+x}{2+x}$$

10

 $$\frac{16-x}{2\left(x+2\right)}$$

9x

$$9x^3$$

$$27x^3$$

$$27x^4$$

$$\frac{3}{x-8}$$

$$\frac{5}{x+8}$$

$$\frac{24+x}{x^2-64}$$

$$\frac{3x-8}{x^2-64}$$

$$\frac{x+1}{4}$$

$$\frac{4}{x^2}$$

$$\frac{1}{2}$$

$$\frac{2}{x^2+2x+1}$$

$$\frac{12x+4}{7x+x^2}$$

$$\frac{14}{x^2}$$

$$\frac{2}{x}$$

$$\frac{4}{x^2}$$

$$\frac{x^2}{3}$$

$$\frac{x^4}{9}$$

$$\frac{9}{x^4}$$

$$\frac{x^2}{9}$$