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Exponential Functions Growth and Decay Word Problems

Total questions: 10

Worksheet time: 10mins

Name
Class
Date
1.

A student invests $500 for 3 years in a savings account that earns 4% interest per year. No further deposits or withdrawals are made during this time. Which statement does not yield the correct balance in the account at the end of 3 years?

a)

500(1.04)^3

b)

500(1 - .04)^3

c)

500(1+.04)(1+.04)(1+.04)

d)

500 + 500(.04) + 520(.04) + 540.8(.04)

2.

Fill in the blank: The principal amount of money is increasing at a ___% interest rate for A = P(1.025)^t.

a)

25

b)

2.5

c)

0.25

d)

52

3.

A particular type of cell triples in number every hour. Which function can be used to find the number of cells present at the end of h hours if there are initially 6 of these cells?

a)

f(h) = 3(6)h

b)

f(h) = 6xh

c)

f(h) = 6(3)h

d)

f(h) = 3(6h)

4.

The amount of cola in a soda machine decreases by a rate of 5% each hour. The amount of cola in the machine was originally 75 gallons. Which function models the amount of cola in gallons after h hours?

a)

f(h) = 75(-5)h

b)

f(h) = -5(75)h

c)

f(h) = .95(75)h

d)

f(h) = 75(.95)h

5.

Write an exponential function to model the situation. Then solve.

The cost of tuition at a college is $12,000 and is increasing at a rate of 6% per year. Which equations represents this situation?

a)

C(t) = 1.06(12000)t

b)

C(t) = 12000(.06)t

c)

C(t) = 12000(.06)t

d)

C(t) = 12000(1.06)t

6.

Write an exponential function to model the situation. You invest $1500. Your investment increases at a rate of 3.5%.

a)

B(t) = 1500(0.965)t

b)

B(t) = 1500(1.035)t

c)

B(t) = 1500(.035)t

d)

B(t) = 1500(1.965)t

7.

The equation f(x) = 300(1.06)x is being used to calculate the amount of money in a savings account.  What does the 1.06 represent?

a)

6% growth

b)

6% decay

c)

1.06% growth

d)

.06% decay

8.

Write an exponential function to model the situation. The value of a car is $18000 and is depreciating at a rate of 12% per year.

a)

V(t) = .88(18000)t

b)

V(t) = .12(18000)t

c)

V(t) = 18000(.88)t

d)

V(t) = 18000(.12)t

9.

What is the a-value (or y-intercept) for the function: f(x) = 800(0.85)x?

a)

800

b)

0.85

c)

0.15

d)

x

10.

The value of a car is $15,000 and depreciates at a rate of 8% per year. What is the exponential equation that models this situation?

a)

y = 8(15,000)x

b)

y = 15,000(1.08)x

c)

y = 15,000(0.92)x

d)

y = 15,000(0.08)x