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WorksheetsPpm Concentration
Total questions: 10
Worksheet time: 20mins
The average mug of tea holds 300 mL of water. If there are 4.2 grams of sugar in a teaspoon, what is the concentration of the sugar in parts per million?
(a)
Contaminated water was found with 22 ppm of mercury within it. What would the mass of mercury in 100 mL of the water be?
(a)
Sulfur dioxide is a pollutant gas which contributes towards acid rain. A 6000 dm3 sample found a volume of 3.7 dm3 of sulfur dioxide in the air. Calculate its concentration in ppm. Give your answer to 3 significant figures.
(a)
A scientist collecting water samples found 1.024 grams of impurities in 10 litres of water. Calculate the impurity concentration in ppm.
(a)
Calculate the total volume of the sample if the concentration of CO2 was 116 ppm, which occupied a volume of 2.4 dm3.
Give your answer to 4 significant figures.
(a)
Calculate the mass of magnesium hydroxide in a 250 mL water solution where the Mg(OH)2 concentration is 300 ppm.
(a)
Calculate the atmospheric concentration of NO2 if 0.85 dm3 of it is found within a 120 dm3 sample of air.
Give your answer as an integer.
(a)
The concentration of calcium ions in a water supply determines whether the water is hard (Ca2+ concentration > 120 ppm) or soft (Ca2+ concentration < 60 ppm). Concentrations between these values are moderate.
If 0.05 g of calcium ions were found in a 750 mL sample, what would the concentration be?
(a)
The concentration of calcium ions in a water supply determines whether the water is hard (Ca2+ concentration > 120 ppm) or soft (Ca2+ concentration < 60 ppm). Concentrations between these values are moderate.
If 0.02 g of calcium ions were found in a 500 mL sample, what would the concentration be?
(a)
The concentration of calcium ions in a water supply determines whether the water is hard (Ca2+ concentration > 120 ppm) or soft (Ca2+ concentration < 60 ppm). Concentrations between these values are moderate.
If 0.004 g of calcium ions were found in a 10 mL sample, what would the concentration be?
(a)
