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Worksheets

Redox Balanced

Total questions: 9

Worksheet time: 24mins

Name
Class
Date
1.

Which species could be reduced to form NO2?

a)

N2O

  

b)

NO3-

    

c)

HNO2

   

d)

NO

2.

What happens to bromine when bromate ions, BrO3- , are converted to bromine molecules, Br2?

a)

 It undergoes reduction and its oxidation state changes from -1 to  0.

 

b)

 It undergoes oxidation and its oxidation state changes from - 1 to 0.

c)

It undergoes reduction and its oxidation state changes from +5 to O.

d)

It undergoes oxidation and its oxidation state changes fron1 +5 to O

3.

What is the reducing agent in the reaction below?

2MnO4 (aq) + Br - (aq) + H2O(l) → 2MnO2(s) +BrO3-+ 2OH-(aq)

a)

Br

 

b)

 BrO3-  

c)

MnO4-

  

d)

MnO2

4.

Which compound contains chlorine with the highest oxidation number?

a)

    NaCl

b)

HOCl

 

c)

Cl2O7

  

d)

ClF

5.

Which of the following is not a redox reaction?

a)

   Zn(NO3)2(aq) + Mg(s) → Mg(NO3)2(aq) + Zn(s)

b)

U(s) + 6ClF(l)  →  UF6(l) + 3Cl2(g)

c)

2NO2(g)  →  N2O4(g)

d)

2SO2(g)  +  O2(g) →  2SO3(g)

6.

Balance the following redox equations for reactions that occur in neutral solution:

Zn + Ag+ → Zn2+ + Ag

a)

  Zn + 2Ag+ →  Zn2+ + 2Ag

  

b)

Zn + Ag+ →  Zn2+ + Ag

c)

  Zn + 2Ag+ → Zn2+ + Ag

d)

Zn+ Ag+ → 2 Zn2+ + 2Ag

7.

Balance the following redox equations for reactions that occur in neutral solution:

Fe3+ + I → Fe2+ + I2. :

a)

Fe3+ + 2I →  Fe2+ + 2I2

b)

Fe3+ +  I →  Fe2+ + I2

c)

2Fe3+ + I →  2Fe2+ + I2

d)

2Fe3+ + 2I →  2Fe2+ + I2

8.

Balance the following half-equations for reactions that occur in acidic solution:

BrO3+ I → Br2 + I2

a)

2BrO3+ 10I + 6H+ → Br2 + 5I2 + 3H2O

b)

2BrO3+ 10I + 12H+ → Br2 + 5I2 + 6H2O

c)

BrO3+ 10I + 14H+ → Br2 + 5I2 + 7H2O

d)

BrO3+ 5I + 12H+ → Br2 + 3I2 + 6H2O

9.

Balance the following half-equations for reactions that occur in acidic solution :

Zn + VO2+ + H+ V3+ + H2O + Zn2+

a)

Zn + 2VO2+ + 4H+ → Zn2+ + 2V3+ + 2H2O

   

b)

Zn + VO2+ + 4H+ → Zn2+ + V3+ + 2H2O

c)

Zn + 2VO2+ + 2H+ → Zn2+ + 2V3+ + H2O

d)

2Zn + 2VO2+ + 4H+ → Zn2+ + 2V3+ + 2H2O