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Total questions: 150
Worksheet time: 7hrs 45mins
Select the true equation
9−2=−81
9−2=181
9−2=811
9−2=−18
9−2=3
Select the true equation
1231=4
1231=312
1231=1231
1231=−4
233
rp=q is equivalent to which of the following statements?
logrp=q
logpq=r
logqr=p
logrq=p
logpr=q
If logmn=6 , which of the following statements is always true?
n=6m
n=m6
m=n6
m=6n
n=6
If log3x=−2 , then the value of x is
−6
−23
32
61
91
True or false?
logx(x1) =−1
TRUE
FALSE
logaa is equal to
21
a1
−a
−2
undefined
log250.2 is equal to
2
−2
21
−21
5
If loga5=x and loga2=y , then loga6250 is equal to?
x+y
5x+y
5x+10y
4x+10y
(x+y)2
log610−log62 is the same as
log68
log60.2
log62log610
log65
log310
2+log53 can be simplified to
2log53
log103
log59
log575
log5125
If logb(a1)=1.2 , then logba is equal to?
−1.44
−2.4
−0.6
3625
−2536
logx(y1)+logxy7 is equivalent to
3logxy
7
6logxy
21logxy7
ylogx7
True or false?
If 52m=5−21 , then 2m=−21
TRUE
FALSE
If your calculator only has a "log" button, the solution to 7x=12 can be calculated:
x=log(712)
x=log12−log7
x=12−log7
x=log7log12
x=log127
If log23x−log25=3 , then x is
340
3
38
1
6
If log3(x+2)+log3(x−2)=1 , then x is:
2
±2
7
±7
Undefined
52 = 25
2-4 = 1/16
log232 = 5
log2(1/8) = -3
log416
Log264
5x = 17
log8(x) = 2
x=4/9
log33x = 5
2-4 = 1/16
log232 = 5
5x = 17
Write as a single logarithm:
log(30)-log(6)
-6log(30)
log(24)
log(-24)
log(5)
ln(2) = x
Rewrite ex = 9 using a logarithm
ln x = 9
ln 9 = x
logx e = 9
log9 x = e
8x+1= 3
6-3x=216
x=3
x=-1
x=6
x=-3
log39 + log327
log2800 - log2100
log5125 - log525
log63 + log62
log381
log6(1/216)
3 log24
3 log82
52 = 25
2-4 = 1/16
log232 = 5
log2(1/8) = -3
Evaluate the following logarithm:
log327
3
2
-3
1/3
Evaluate the following logarithm:
log416
1
-2
2
1/2
Evaluate the following logarithm:
log55
1
0
-1
1/2
log6(1/216)
Rewrite log28 = 3 in exponential form
28 = 3
23 = 8
32 = 8
83 = 2
Evaluate the following logarithm:
log327
3
2
-3
1/3
Evaluate the following logarithm:
log55
1
0
-1
1/2
Evaluate the following logarithm:
log33
1
0
-1
1/2
Evaluate the following logarithm:
log416
1
-2
2
1/2
Evaluate the following logarithm:
log42
-1/2
-2
2
1/2
Evaluate the following logarithm:
log8√8
-1/2
-1
1
1/2
Evaluate the following logarithm:
log2√2
-1/2
-1
1
1/2
Evaluate the following logarithm:
log250.2
-1/2
-2
2
1/2
Evaluate the following logarithm:
log40.5
-1/2
-2
2
1/2
Evaluate the following logarithm:
log121
1
0
-1
1/2
Evaluate the following logarithm:
log151
1
0
-1
1/2
Evaluate the following logarithm:
log3(1/3)
-2
-1/2
-1
1/2
Evaluate the following logarithm:
log4(1/64)
3
-1/3
-3
1/3
Evaluate the following logarithm:
log273
1/3
-3
-1/2
1/2
Evaluate the following logarithm:
log84
2/3
3/2
3/4
1/2
Evaluate the following logarithm:
log25125
2/3
3/2
3/4
1/2
Evaluate the following logarithm:
log8127
2/3
3/2
3/4
4/3
Evaluate the following logarithm:
log1632
4/3
3/4
5/4
4/5
Evaluate the following logarithm:
log636
3
2
1
0
Evaluate the following logarithm:
log66
3
2
1
0
log36+log32 =
log364
log33
log312
log336
log36−log32 =
log364
log33
log312
log336
2log36 =
log364
log33
log312
log336
Logarithmic form of 43=64 is
log43= 64
log34= 64
log644= 3
log464= 3
Evaluate log28 .
3
4
16
64
Exponential form of log7 49=2 is
logaxy=
logax+logay
logax−logay
loga x+y
mloga x
loga (yx)=
logax+logay
logax−logay
loga x+y
mloga x
loga xm=
logax+logay
logax−logay
loga x+y
mloga x
aloga n=
logax+logay
logax−logay
n
a
loga a =
Not defined
0
1
a
loga 1 =
Not defined
0
1
a
loga 0 =
Not defined
0
1
a
3 log36=
log3216
6
log312
log336
log100.01 =
1
2
-1
-2
logx x =
1
2
21
x
log10 1000=
3
2
-3
-2
log7 1 =
Not defined
0
1
a
log102 is
Rational number
Irrational number
Integer
Natural number
log25 5 =
1
25
21
5
log216
8
4
6
log5625
5
4
25
log5 251
21
2
-2
log31 9
31
2
-2
log31 91
31
2
-2
log41 16
31
2
-2
log25 + log 4
31
2
-2
log230 − log215
1
2
-2
2log210=... .
log 10
log 2
10
3 log24
log(yz8x)
log8+logx-logy-logz
log8+logx-logy+logz
log(8x)-log(yz)
8logx-ylogz
log(3x)2
2log(3+x)
2log3+logx
log3+2logx
2(log3+logx)
ln(4xy)
ln4+lnx+lny
4lnxy
4lnx+lny
4ln(x+y)
log(nm3)
logm-log3-logn
3logm+logn
3logm-logn
3log(m-n)
log(x7)
log(7x)
log7+logx
xlog7
7logx
log(49)
log9+log4
log(9-4)
log9-log4
4log9
log4x2=log43+log4(x+6)
Which quadratic equation would you wind up solving when solving the log equation?
x2−3x−18=0
x2+3x+6=0
x2−3x−6=0
x2−x−9=0
4log2(2x+24)−17=−9
Once you have isolated the log in the equation, what would be the next step?
log both sides
rewrite as an exponential
nothing, you would not be able to solve it
divide both sides by 2
log232=3x
5/3
3/5
5
3
log4(3x-1)=log4(2x+3)
4
3
1
8
logx1000=3
1
10
30
3
log8(4x+4)=2
15
12
10
3
42x + 1 = 17
log8(1/2) = x
-1/3
1/3
1/2
-1/2
Solve
log5x+logx25=35
10
25
30
Solve
7logx3−log3x=60
3
3−3
3−7
Solve the equation.
0
2/3
3/2
1
log x + log 8 = 2
Finish solving for x.
Fill in the blank in the box below
(a)
Continue solving for x. Which is the correct "step 2"?
64=x3
643=x
x64=3
364=x
We want to solve for x. Which of these is the correct "step 1"?
log(64)=log(3x)
log(16)=log(x3)
log(16)=log(3x)
log(64)=log(x3)
log(1)=log(x3)
Solve the equation log8(−4r−3)=log8(4r+5)
1/3
7
-1
-1/14
Solve for x.
2log410=log4(8x)+log4(5)
x = 2.5
x = 0.5
x = 1.538
x = 11.875
Solve for x. log52+log5x=log520
x = 20
x = 10
x = 2
x=101
You want to solve for x. Which of these is the correct "step 1"?
log78=log7x
log742=log7x
log748=log7(6x)
log754=log7x
We want to solve for x. What's the first step?
Rewrite as a logarithm: log1893=x
Rewrite as a logarithm: log3189=x
Rewrite 189 with a base of 3: 3x=363
Rewrite 189 with a base of 3: 3x=39
We want to solve for x. Which of these is the correct "step 1"?
log(64)=log(3x)
log(16)=log(x3)
log(16)=log(3x)
log(64)=log(x3)
log(1)=log(x3)
Which is the correct "step 1" to solve for x?
Hint: look at the schoology discussions if you feel stuck
log2(100x5)=7
log2(95x)=7
log2(20x)=7
log2(500x)=7
Solve for x.
log52+log5x=log520
x = (a)
Solve for x.
2log410=log4(8x)+log4(5)
x = 2.5
x = 0.5
x = 1.538
x = 11.875
