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Total questions: 61
Worksheet time: 3570secs
∫∫∫(2x−3y+4z)dxdydz
xyz(x+23y+2z)+C
xyz(x−3y+2z)+C
xyz(x−23y+2z)+C
xyz(x+3y+2z)+C
∫∫∫(x2+y2+z2)dxdydz
3xyz(x2yz+xy2z+xyz2)+C
31xyz(x2+y2+z2)+C
xyz(x2yz+xy2z+xyz2)+C
31xyz(x2y2z+xy2z2+x2yz2)+C
∫∫∫e4xdxdydz
31e4xyyz+C
31e4xyz+C
41e4xxyz+C
41e4xyz+C
∫01∫12∫34 (−x−y−z)dxdydz
5.50
-5.50
8.50
-8.50
∫24∫68∫−2−4 cos(y) dxdydz
−8.05
≈−0.192
≈−2.19
≈−5.08
∫24∫68∫−2−4 (ez) dxdydz
≈−189
≈−132
≈538
≈710
Find the lower limit of z in the triple integral
∫∫∫D f(x,y,z)dV if D is the solid bounded by z=4−y, z=y−6 and y=x2, taking the order of integration as dzdydx .5
y−6
4−y
0
Find the upper limit of z in the triple integral
∫∫∫D f(x,y,z)dV if D is the solid bounded by z=4−y, z=y−6 and y=x2, taking the order of integration as dzdydx .5
y−6
4−y
0
Find the upper limit of y in the triple integral
∫∫∫D f(x,y,z)dV if D is the solid bounded by z=4−y, z=y−6 and y=x2, taking the order of integration as dzdydx .x2
5
z+6
0
∫∫∫(2x−3y+4z)dxdydz
xyz(x+23y+2z)+C
xyz(x−3y+2z)+C
xyz(x−23y+2z)+C
xyz(x+3y+2z)+C
∫∫∫(x2+y2+z2)dxdydz
3xyz(x2yz+xy2z+xyz2)+C
31xyz(x2+y2+z2)+C
xyz(x2yz+xy2z+xyz2)+C
31xyz(x2y2z+xy2z2+x2yz2)+C
∫∫∫e4xdxdydz
31e4xyyz+C
31e4xyz+C
41e4xxyz+C
41e4xyz+C
∫01∫12∫34 (−x−y−z)dxdydz
5.50
-5.50
8.50
-8.50
∫24∫68∫−2−4 cos(y) dxdydz
−8.05
≈−0.192
≈−2.19
≈−5.08
∫24∫68∫−2−4 (ez) dxdydz
≈−189
≈−132
≈538
≈710
Find the lower limit of z in the triple integral
∫∫∫D f(x,y,z)dV if D is the solid bounded by z=4−y, z=y−6 and y=x2, taking the order of integration as dzdydx .5
y−6
4−y
0
Find the upper limit of z in the triple integral
∫∫∫D f(x,y,z)dV if D is the solid bounded by z=4−y, z=y−6 and y=x2, taking the order of integration as dzdydx .5
y−6
4−y
0
Find the lower limit of y in the triple integral
∫∫∫D f(x,y,z)dV if D is the solid bounded by z=4−y, z=y−6 and y=x2, taking the order of integration as dzdydx .x2
5
z+6
0
Find the upper limit of y in the triple integral
∫∫∫D f(x,y,z)dV if D is the solid bounded by z=4−y, z=y−6 and y=x2, taking the order of integration as dzdydx .x2
5
z+6
0
Find the lower limit of x in the triple integral
∫∫∫D f(x,y,z)dV if D is the solid bounded by z=4−y, z=y−6 and y=x2, taking the order of integration as dzdydx . 5
−5
5
−5
Find the upper limit of x in the triple integral
∫∫∫D f(x,y,z)dV if D is the solid bounded by z=4−y, z=y−6 and y=x2, taking the order of integration as dzdydx . 5
−5
5
−5
Find the volume of the solid D (leave your answer correct to two decimal places) in the triple integral
∫∫∫D f(x,y,z)dV if D is the solid bounded by z=4−y, z=y−6 and y=x2.
(a)
Determine the intervals for r and θ associated with the blue region.
3≤r≤4, 0≤θ≤π
2≤r≤4, 0≤θ≤4π
π≤r≤4π, 1≤θ≤4
2≤r≤4, 4π≤θ≤π
Convert ∫021∫x1−x2(3x +4y2) dydx into polar coordinates
∫04π∫013r+4rsinθ drdθ
∫4π2π∫01r2(3cosθ+4rsin2θ)drdθ
∫02π∫013rcosθ+4r2sin2θ drdθ
∫3π2π∫013cosθ+4r2sin2θ r drdθ
Set up limit of triple integral to find the volume of the solid that lies below the hemisphere z=25−x2−y2 between cylinder x2+y2=16 and x2+y2=25 using cylindrical coordinates.
∫02π∫04∫025−r2rdzdrdθ
∫02π∫05∫025−r2rdzdrdθ
∫02π∫45∫025−r2rdzdrdθ
∫02π∫45∫05rdzdrdθ
In ∫01∫01−z∫01−y−zxyzdxdydz the limit of x varies from____________
0 to 1
0 to 1-z
0 to 1-y-z
1 to 1-y-z
Determine the intervals for r and θ associated with the blue region.
3≤r≤4, 0≤θ≤π
2≤r≤4, 0≤θ≤4π
π≤r≤4π, 1≤θ≤4
2≤r≤4, 4π≤θ≤π
Find the upper limit of z in the triple integral
∫∫∫D f(x,y,z)dV if D is the solid bounded by z=4−y, z=y−6 and y=x2, taking the order of integration as dzdydx .5
y−6
4−y
0
Find the upper limit of z in the triple integral
∫∫∫D f(x,y,z)dV if D is the solid bounded by z=4−y, z=y−6 and y=x2, taking the order of integration as dzdydx .5
y−6
4−y
0
Find the lower limit of z in the triple integral
∫∫∫D f(x,y,z)dV if D is the solid bounded by z=4−y, z=y−6 and y=x2, taking the order of integration as dzdydx .5
y−6
4−y
0
Find the upper limit of y in the triple integral
∫∫∫D f(x,y,z)dV if D is the solid bounded by z=4−y, z=y−6 and y=x2, taking the order of integration as dzdydx .x2
5
z+6
0
Find the lower limit of y in the triple integral
∫∫∫D f(x,y,z)dV if D is the solid bounded by z=4−y, z=y−6 and y=x2, taking the order of integration as dzdydx .x2
5
z+6
0
Find the upper limit of x in the triple integral
∫∫∫D f(x,y,z)dV if D is the solid bounded by z=4−y, z=y−6 and y=x2, taking the order of integration as dzdydx . 5
−5
5
−5
Find the lower limit of x in the triple integral
∫∫∫D f(x,y,z)dV if D is the solid bounded by z=4−y, z=y−6 and y=x2, taking the order of integration as dzdydx . 5
−5
5
−5
Find the volume of the solid D (leave your answer correct to two decimal places) in the triple integral
∫∫∫D f(x,y,z)dV if D is the solid bounded by z=4−y, z=y−6 and y=x2.
(a)
∫0π/2∫0π/2cosθcosφdθdφ is ___________
1
0
π
2π
∫12∫02exdydx is ___________
e2−e
2(e2−e)
e2
e2−1
Find the volume of the solid D (leave your answer correct to two decimal places) in the triple integral
∫∫∫D f(x,y,z)dV if D is the solid bounded by z=4−y, z=y−6 and y=x2.
(a)
Set up limit of triple integral to find the volume of the solid that lies below the hemisphere z=25−x2−y2 between cylinder x2+y2=16 and x2+y2=25 using cylindrical coordinates.
∫02π∫04∫025−r2rdzdrdθ
∫02π∫05∫025−r2rdzdrdθ
∫02π∫45∫025−r2rdzdrdθ
∫02π∫45∫05rdzdrdθ
∫02∫0∞e−xdxdy is ___________
2
1
e2−1
e−2−1
∫12∫02exdydx is ___________
e2−e
2(e2−e)
e2
e2−1
∫02∫0yx2dxdy is ___________
32
34
31
35
¿ Cuál de las siguientes imágenes es una coordenada cilíndrica?
Región determinada por
2≤r≤4 , 0≤z≤3 , 0≤θ≤2π
∫01∫−4−x24−x2 ∫x2+y24 x dzdydx . Si a la integral dada le realizamos un cambio de variable a coordenadas cilíndricas obtenemos:
∫02π∫02∫r24 r2senθ dzdrdθ
∫02π∫02∫r24 r2cosθ dzdrdθ
∫02∫02π∫r24 r2cosθ dzdrdθ
∫02π∫02∫r24 r2cosθ dzdθdr
Describir la región dada en coordenadas esféricas
E={0≤θ≤2π; 0≤ϕ≤2π; 9≤ρ≤25}
E={0≤θ≤2π; 0≤ϕ≤4π; 3≤ρ≤5}
E={0≤θ≤2π; 0≤ϕ≤3π; 3≤ρ≤5}
Se tiene el sólido E encerrada por las superficies S1: z=8−x2−y2 ; S2: z =x2+y2 . La descripción del solido en coordenadas esféricas es::
E={0≤θ≤2π; 0≤ϕ≤4π; 0≤ρ≤8}
E={0≤θ≤2π; 0≤ϕ≤2π; 0≤ρ≤8}
E={0≤θ≤2π; 0≤ϕ≤2π; 0≤ρ≤8}
Find the cylindrical coordinate for the Cartesian coordinate
(x,y,z)=(1,−1, 3).(2,4π,3)
(2,−4π,3)
(11,4π,3)
(11,−4π,3)
Set up the limit of triple integral to find the volume of the solid bounded by z=4−x2 , y+z=5 ,z=0, y=0
Evaluate the triple integral
∫∫∫E6xy dV where E lies under the plane z=1+x+y and above the region in the xy-plane bounded by the curves y=x , y=0, x=1 . The result is equal to (a) (Please write in a fraction term a/b)
Calculate the value of the multiple integral ∫∫D(x2+y2)23dA , where D is the region in the first quadrant bounded by the lines y=0 and y=3x and the circle x2+y2=9 . The result is equal to___
581π
527π
59π
53π
Is it TRUE or FALSE:
∫−12∫05x2sin(x−y)dxdy=∫05∫−12x2sin(x−y)dydx
TRUE
FALSE
What is the formula for calculating the volume of a solid using a triple integral?
∭∭∭ f(x, y, z) dV
∬∬∬ f(x, y, z) dV
∭∭ f(x, y, z) dV
∫∫∫ f(x, y, z) dV
What is the concept of iterated integrals?
A mathematical concept used to calculate multiple integrals by breaking the region into smaller pieces and integrating over each piece.
A cooking technique used to prepare multiple dishes simultaneously
A concept in computer programming for repeating a sequence of instructions
A method for solving algebraic equations using repeated addition
How do you determine the limits of integration for a double integral?
Guess randomly
Consider the region of integration and the bounds of the variables involved.
Use the value of the function at a single point
Ask someone else to determine the limits
Calcula el área bajo la curva
y=8x(x2−1)10 comprendida entre x=0 y x=1.114u2
−52u2
−118u2
52u2
Determine el valor de la integral que se muestra en la imagen
200
49
15
175
Responder: ¿Qué es un integral definida?
Una función
Una antiderivada
Un diferencial
Un límite de sumas
El valor de la integral ∫−11x3dx es:
Positivo
Negativo
Cero
No se puede determinar
10.5
21
11
12.5
Una suma de Riemann que permite calcular la integral ∫12(3x2−2x)dx es:
n→∞limk=1∑∞(3 n2k2−2 nk) n1
n→∞limk=1∑∞(n1+4 n2k+3 n3k2 )
n→∞limk=1∑∞(3 (1+nk)2+2 (1+nk)) n1
Ninguna de las anteriores
