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Total questions: 61

Worksheet time: 3570secs

Name
Class
Date
1.

∫∫∫(2x−3y+4z)dxdydz\int\int\int\left(2x-3y+4z\right)dxdydz  

a)

xyz(x+32y+2z)+Cxyz\left(x+\frac{3}{2}y+2z\right)+C  

b)

xyz(x−3y+2z)+Cxyz\left(x-3y+2z\right)+C  

c)

xyz(x−32y+2z)+Cxyz\left(x-\frac{3}{2}y+2z\right)+C  

d)

xyz(x+3y+2z)+Cxyz\left(x+3y+2z\right)+C  

2.

∫∫∫(x2+y2+z2)dxdydz\int\int\int\left(x^2+y^2+z^2\right)dxdydz  

a)

3xyz(x2yz+xy2z+xyz2)+C3xyz\left(x^2yz+xy^2z+xyz^2\right)+C  

b)

13xyz(x2+y2+z2)+C\frac{1}{3}xyz\left(x^2+y^2+z^2\right)+C  

c)

xyz(x2yz+xy2z+xyz2)+Cxyz\left(x^2yz+xy^2z+xyz^2\right)+C  

d)

13xyz(x2y2z+xy2z2+x2yz2)+C\frac{1}{3}xyz\left(x^2y^2z+xy^2z^2+x^2yz^2\right)+C  

3.

∫∫∫e4xdxdydz\int\int\int e^{4x}dxdydz  

a)

13e4xyyz+C\frac{1}{3}e^{4xy}yz+C  

b)

13e4xyz+C\frac{1}{3}e^{4x}yz+C  

c)

14e4xxyz+C\frac{1}{4}e^{4x}xyz+C  

d)

14e4xyz+C\frac{1}{4}e^{4x}yz+C  

4.

∫01∫12∫34 (−x−y−z)dxdydz\int_0^1\int_1^2\int_3^4\ \left(-x-y-z\right)dxdydz  

a)

5.50

b)

-5.50

c)

8.50

d)

-8.50

5.

∫24∫68∫−2−4 cos⁡(y) dxdydz\int_2^4\int_6^8\int_{-2}^{-4}\ \cos\left(y\right)\ dxdydz  

a)

−8.05-8.05  

b)

≈−0.192\approx-0.192  

c)

≈−2.19\approx-2.19  

d)

≈−5.08\approx-5.08  

6.

∫24∫68∫−2−4 (ez) dxdydz\int_2^4\int_6^8\int_{-2}^{-4}\ \left(e^z\right)\ dxdydz  

a)

≈−189\approx-189  

b)

≈−132\approx-132  

c)

≈538\approx538  

d)

≈710\approx710  

7.

Find the lower limit of z in the triple integral

∫∫∫D  f(x,y,z)dV\int_{ }^{ }\int_{ }^{ }\int_D^{ }\ \ f\left(x,y,z\right)dV  if D is the solid bounded by  z=4−y, z=y−6z=4-y,\ z=y-6  and  y=x2,y=x^2,  taking the order of integration as dzdydxdzdydx  .

a)

55  

b)

y−6y-6  

c)

4−y4-y  

d)

00  

8.

Find the upper limit of z in the triple integral

∫∫∫D  f(x,y,z)dV\int_{ }^{ }\int_{ }^{ }\int_D^{ }\ \ f\left(x,y,z\right)dV  if D is the solid bounded by  z=4−y, z=y−6 z=4-y,\ z=y-6\  and  y=x2,y=x^2,  taking the order of integration as dzdydxdzdydx  .

a)

55  

b)

y−6y-6  

c)

4−y4-y  

d)

00  

9.

Find the upper limit of y in the triple integral

∫∫∫D  f(x,y,z)dV\int_{ }^{ }\int_{ }^{ }\int_D^{ }\ \ f\left(x,y,z\right)dV  if D is the solid bounded by  z=4−y, z=y−6z=4-y,\ z=y-6  and  y=x2,y=x^2,  taking the order of integration as dzdydxdzdydx  .

a)

x2x^2  

b)

55  

c)

z+6z+6  

d)

00  

10.

∫∫∫(2x−3y+4z)dxdydz\int\int\int\left(2x-3y+4z\right)dxdydz  

a)

xyz(x+32y+2z)+Cxyz\left(x+\frac{3}{2}y+2z\right)+C  

b)

xyz(x−3y+2z)+Cxyz\left(x-3y+2z\right)+C  

c)

xyz(x−32y+2z)+Cxyz\left(x-\frac{3}{2}y+2z\right)+C  

d)

xyz(x+3y+2z)+Cxyz\left(x+3y+2z\right)+C  

11.

∫∫∫(x2+y2+z2)dxdydz\int\int\int\left(x^2+y^2+z^2\right)dxdydz  

a)

3xyz(x2yz+xy2z+xyz2)+C3xyz\left(x^2yz+xy^2z+xyz^2\right)+C  

b)

13xyz(x2+y2+z2)+C\frac{1}{3}xyz\left(x^2+y^2+z^2\right)+C  

c)

xyz(x2yz+xy2z+xyz2)+Cxyz\left(x^2yz+xy^2z+xyz^2\right)+C  

d)

13xyz(x2y2z+xy2z2+x2yz2)+C\frac{1}{3}xyz\left(x^2y^2z+xy^2z^2+x^2yz^2\right)+C  

12.

∫∫∫e4xdxdydz\int\int\int e^{4x}dxdydz  

a)

13e4xyyz+C\frac{1}{3}e^{4xy}yz+C  

b)

13e4xyz+C\frac{1}{3}e^{4x}yz+C  

c)

14e4xxyz+C\frac{1}{4}e^{4x}xyz+C  

d)

14e4xyz+C\frac{1}{4}e^{4x}yz+C  

13.

∫01∫12∫34 (−x−y−z)dxdydz\int_0^1\int_1^2\int_3^4\ \left(-x-y-z\right)dxdydz  

a)

5.50

b)

-5.50

c)

8.50

d)

-8.50

14.

∫24∫68∫−2−4 cos⁡(y) dxdydz\int_2^4\int_6^8\int_{-2}^{-4}\ \cos\left(y\right)\ dxdydz  

a)

−8.05-8.05  

b)

≈−0.192\approx-0.192  

c)

≈−2.19\approx-2.19  

d)

≈−5.08\approx-5.08  

15.

∫24∫68∫−2−4 (ez) dxdydz\int_2^4\int_6^8\int_{-2}^{-4}\ \left(e^z\right)\ dxdydz  

a)

≈−189\approx-189  

b)

≈−132\approx-132  

c)

≈538\approx538  

d)

≈710\approx710  

16.

Find the lower limit of z in the triple integral

 ∫∫∫D  f(x,y,z)dV\int_{ }^{ }\int_{ }^{ }\int_D^{ }\ \ f\left(x,y,z\right)dV  if D is the solid bounded by  z=4−y, z=y−6z=4-y,\ z=y-6  and  y=x2,y=x^2,  taking the order of integration as  dzdydxdzdydx  .

a)

 55  

b)

 y−6y-6  

c)

 4−y4-y  

d)

 00  

17.

Find the upper limit of z in the triple integral

 ∫∫∫D  f(x,y,z)dV\int_{ }^{ }\int_{ }^{ }\int_D^{ }\ \ f\left(x,y,z\right)dV  if D is the solid bounded by  z=4−y, z=y−6 z=4-y,\ z=y-6\   and  y=x2,y=x^2,  taking the order of integration as  dzdydxdzdydx  .

a)

 55  

b)

 y−6y-6  

c)

 4−y4-y  

d)

 00  

18.

Find the lower limit of y in the triple integral

 ∫∫∫D  f(x,y,z)dV\int_{ }^{ }\int_{ }^{ }\int_D^{ }\ \ f\left(x,y,z\right)dV  if D is the solid bounded by  z=4−y, z=y−6z=4-y,\ z=y-6  and  y=x2,y=x^2,  taking the order of integration as  dzdydxdzdydx  .

a)

 x2x^2  

b)

 55  

c)

 z+6z+6  

d)

 00  

19.

Find the upper limit of y in the triple integral

 ∫∫∫D  f(x,y,z)dV\int_{ }^{ }\int_{ }^{ }\int_D^{ }\ \ f\left(x,y,z\right)dV  if D is the solid bounded by  z=4−y, z=y−6z=4-y,\ z=y-6  and  y=x2,y=x^2,  taking the order of integration as  dzdydxdzdydx  .

a)

 x2x^2  

b)

 55  

c)

 z+6z+6  

d)

 00  

20.

Find the lower limit of x in the triple integral

 ∫∫∫D  f(x,y,z)dV\int_{ }^{ }\int_{ }^{ }\int_D^{ }\ \ f\left(x,y,z\right)dV  if D is the solid bounded by  z=4−y, z=y−6z=4-y,\ z=y-6  and  y=x2,y=x^2,  taking the order of integration as  dzdydxdzdydx  .

a)

 55  

b)

 −5-5  

c)

 5\sqrt{5}  

d)

 −5-\sqrt{5}  

21.

Find the upper limit of x in the triple integral

 ∫∫∫D  f(x,y,z)dV\int_{ }^{ }\int_{ }^{ }\int_D^{ }\ \ f\left(x,y,z\right)dV  if D is the solid bounded by  z=4−y, z=y−6z=4-y,\ z=y-6  and  y=x2,y=x^2,  taking the order of integration as  dzdydxdzdydx  .

a)

 55  

b)

 −5-5  

c)

 5\sqrt{5}  

d)

 −5-\sqrt{5}  

22.

Find the volume of the solid D (leave your answer correct to two decimal places) in the triple integral

 ∫∫∫D  f(x,y,z)dV\int_{ }^{ }\int_{ }^{ }\int_D^{ }\ \ f\left(x,y,z\right)dV  if D is the solid bounded by  z=4−y, z=y−6z=4-y,\ z=y-6  and  y=x2.y=x^2. 



(a)  

23.

Determine the intervals for  rr   and  θ\theta  associated with the blue region.

a)

3≤r≤4, 0≤θ≤π3\le r\le4,\ 0\le\theta\le\pi  

b)

2≤r≤4, 0≤θ≤π42\le r\le4,\ 0\le\theta\le\frac{\pi}{4}  

c)

π≤r≤π4, 1≤θ≤4\pi\le r\le\frac{\pi}{4},\ 1\le\theta\le4  

d)

2≤r≤4, π4≤θ≤π2\le r\le4,\ \frac{\pi}{4}\le\theta\le\pi  

24.

Convert  ∫012∫x1−x2(3x +4y2) dydx\int_0^{\frac{1}{\sqrt{2}}}\int_x^{\sqrt{1-x^2}}\left(3x\ +4y^2\right)\ dydx  into polar coordinates

a)

∫0π4∫013r+4rsin⁡θ drdθ\int_0^{\frac{\pi}{4}}\int_0^13r+4r\sin\theta\ drd\theta  

b)

∫π4π2∫01r2(3cos⁡θ+4rsin⁡2θ)drdθ\int_{\frac{\pi}{4}}^{\frac{\pi}{2}}\int_0^1r^2\left(3\cos\theta+4r\sin^2\theta\right)drd\theta  

c)

∫0π2∫013rcos⁡θ+4r2sin⁡2θ drdθ\int_0^{\frac{\pi}{2}}\int_0^13r\cos\theta+4r^2\sin^2\theta\ drd\theta  

d)

∫π3π2∫013cos⁡θ+4r2sin⁡2θ r drdθ\int_{\frac{\pi}{3}}^{\frac{\pi}{2}}\int_0^13\cos\theta+4r^2\sin^2\theta\ r\ drd\theta  

25.

Set up limit of triple integral to find the volume of the solid that lies below the hemisphere  z=25−x2−y2z=\sqrt{25-x^2-y^2} between cylinder  x2+y2=16x^2+y^2=16   and  x2+y2=25x^2+y^2=25  using cylindrical coordinates.

a)

∫02π∫04∫025−r2rdzdrdθ\int_0^{2\pi}\int_0^4\int_0^{\sqrt{25-r^2}}rdzdrd\theta  

b)

∫02π∫05∫025−r2rdzdrdθ\int_0^{2\pi}\int_0^5\int_0^{\sqrt{25-r^2}}rdzdrd\theta  

c)

∫02π∫45∫025−r2rdzdrdθ\int_0^{2\pi}\int_4^5\int_0^{\sqrt{25-r^2}}rdzdrd\theta  

d)

∫02π∫45∫05rdzdrdθ\int_0^{2\pi}\int_4^5\int_0^5rdzdrd\theta  

26.

In ∫01∫01−z∫01−y−zxyzdxdydz\int_0^1\int_0^{1-z}\int_0^{1-y-z}xyzdxdydz the limit of x varies from____________

a)

0 to 1

b)

0 to 1-z

c)

0 to 1-y-z

d)

1 to 1-y-z

27.

Determine the intervals for  rr   and  θ\theta  associated with the blue region.

a)

3≤r≤4, 0≤θ≤π3\le r\le4,\ 0\le\theta\le\pi  

b)

2≤r≤4, 0≤θ≤π42\le r\le4,\ 0\le\theta\le\frac{\pi}{4}  

c)

π≤r≤π4, 1≤θ≤4\pi\le r\le\frac{\pi}{4},\ 1\le\theta\le4  

d)

2≤r≤4, π4≤θ≤π2\le r\le4,\ \frac{\pi}{4}\le\theta\le\pi  

28.

Find the upper limit of z in the triple integral

 ∫∫∫D  f(x,y,z)dV\int_{ }^{ }\int_{ }^{ }\int_D^{ }\ \ f\left(x,y,z\right)dV  if D is the solid bounded by  z=4−y, z=y−6 z=4-y,\ z=y-6\   and  y=x2,y=x^2,  taking the order of integration as  dzdydxdzdydx  .

a)

 55  

b)

 y−6y-6  

c)

 4−y4-y  

d)

 00  

29.

Find the upper limit of z in the triple integral

 ∫∫∫D  f(x,y,z)dV\int_{ }^{ }\int_{ }^{ }\int_D^{ }\ \ f\left(x,y,z\right)dV  if D is the solid bounded by  z=4−y, z=y−6 z=4-y,\ z=y-6\   and  y=x2,y=x^2,  taking the order of integration as  dzdydxdzdydx  .

a)

 55  

b)

 y−6y-6  

c)

 4−y4-y  

d)

 00  

30.

Find the lower limit of z in the triple integral

 ∫∫∫D  f(x,y,z)dV\int_{ }^{ }\int_{ }^{ }\int_D^{ }\ \ f\left(x,y,z\right)dV  if D is the solid bounded by  z=4−y, z=y−6z=4-y,\ z=y-6  and  y=x2,y=x^2,  taking the order of integration as  dzdydxdzdydx  .

a)

 55  

b)

 y−6y-6  

c)

 4−y4-y  

d)

 00  

31.

Find the upper limit of y in the triple integral

 ∫∫∫D  f(x,y,z)dV\int_{ }^{ }\int_{ }^{ }\int_D^{ }\ \ f\left(x,y,z\right)dV  if D is the solid bounded by  z=4−y, z=y−6z=4-y,\ z=y-6  and  y=x2,y=x^2,  taking the order of integration as  dzdydxdzdydx  .

a)

 x2x^2  

b)

 55  

c)

 z+6z+6  

d)

 00  

32.

Find the lower limit of y in the triple integral

 ∫∫∫D  f(x,y,z)dV\int_{ }^{ }\int_{ }^{ }\int_D^{ }\ \ f\left(x,y,z\right)dV  if D is the solid bounded by  z=4−y, z=y−6z=4-y,\ z=y-6  and  y=x2,y=x^2,  taking the order of integration as  dzdydxdzdydx  .

a)

 x2x^2  

b)

 55  

c)

 z+6z+6  

d)

 00  

33.

Find the upper limit of x in the triple integral

 ∫∫∫D  f(x,y,z)dV\int_{ }^{ }\int_{ }^{ }\int_D^{ }\ \ f\left(x,y,z\right)dV  if D is the solid bounded by  z=4−y, z=y−6z=4-y,\ z=y-6  and  y=x2,y=x^2,  taking the order of integration as  dzdydxdzdydx  .

a)

 55  

b)

 −5-5  

c)

 5\sqrt{5}  

d)

 −5-\sqrt{5}  

34.

Find the lower limit of x in the triple integral

 ∫∫∫D  f(x,y,z)dV\int_{ }^{ }\int_{ }^{ }\int_D^{ }\ \ f\left(x,y,z\right)dV  if D is the solid bounded by  z=4−y, z=y−6z=4-y,\ z=y-6  and  y=x2,y=x^2,  taking the order of integration as  dzdydxdzdydx  .

a)

 55  

b)

 −5-5  

c)

 5\sqrt{5}  

d)

 −5-\sqrt{5}  

35.

Find the volume of the solid D (leave your answer correct to two decimal places) in the triple integral

 ∫∫∫D  f(x,y,z)dV\int_{ }^{ }\int_{ }^{ }\int_D^{ }\ \ f\left(x,y,z\right)dV  if D is the solid bounded by  z=4−y, z=y−6z=4-y,\ z=y-6  and  y=x2.y=x^2. 



(a)  

36.

∫0π/2∫0π/2cos⁡θcos⁡φdθdφ\int_0^{\pi/2}\int_0^{\pi/2}\cos\theta\cos\varphi d\theta d\varphi  is ___________

a)

1

b)

0

c)

π\pi  

d)

π2\frac{\pi}{2}  

37.

∫12∫02exdydx\int_1^2\int_0^2e^xdydx is ___________

a)

e2−ee^2-e  

b)

2(e2−e)2\left(e^2-e\right)  

c)

e2e^2  

d)

e2−1e^2-1  

38.

Find the volume of the solid D (leave your answer correct to two decimal places) in the triple integral

∫∫∫D  f(x,y,z)dV\int_{ }^{ }\int_{ }^{ }\int_D^{ }\ \ f\left(x,y,z\right)dV  if D is the solid bounded by  z=4−y, z=y−6z=4-y,\ z=y-6  and  y=x2.y=x^2.



(a)  

39.

Set up limit of triple integral to find the volume of the solid that lies below the hemisphere  z=25−x2−y2z=\sqrt{25-x^2-y^2} between cylinder  x2+y2=16x^2+y^2=16   and  x2+y2=25x^2+y^2=25  using cylindrical coordinates.

a)

∫02π∫04∫025−r2rdzdrdθ\int_0^{2\pi}\int_0^4\int_0^{\sqrt{25-r^2}}rdzdrd\theta  

b)

∫02π∫05∫025−r2rdzdrdθ\int_0^{2\pi}\int_0^5\int_0^{\sqrt{25-r^2}}rdzdrd\theta  

c)

∫02π∫45∫025−r2rdzdrdθ\int_0^{2\pi}\int_4^5\int_0^{\sqrt{25-r^2}}rdzdrd\theta  

d)

∫02π∫45∫05rdzdrdθ\int_0^{2\pi}\int_4^5\int_0^5rdzdrd\theta  

40.

∫02∫0∞e−xdxdy\int_0^2\int_0^{\infty}e^{-x}dxdy  is ___________

a)

2

b)

1

c)

e2−1e^2-1  

d)

e−2−1e^{-2}-1  

41.

∫12∫02exdydx\int_1^2\int_0^2e^xdydx is ___________

a)

e2−ee^2-e  

b)

2(e2−e)2\left(e^2-e\right)  

c)

e2e^2  

d)

e2−1e^2-1  

42.

∫02∫0yx2dxdy\int_0^2\int_0^yx^2dxdy  is ___________

a)

23\frac{2}{3}  

b)

43\frac{4}{3}  

c)

13\frac{1}{3}  

d)

53\frac{5}{3}  

43.

¿ Cuál de las siguientes imágenes es una coordenada cilíndrica?

a)
b)
c)
d)
44.

Región determinada por

2≤r≤4 , 0≤z≤3 ,  0≤θ≤π2 2\le r\le4\ ,\ 0\le z\le3\ ,\ \ 0\le\theta\le\frac{\pi}{2}\  

a)
b)
c)
d)
45.

∫01∫−4−x24−x2 ∫x2+y24    x dzdydx\int_0^1\int_{-\sqrt{4-x^2}}^{\sqrt{4-x^2}}\ \int_{x^2+y^2}^4\ \ \ \ x\ dzdydx  . Si a la integral dada le realizamos un cambio de variable a coordenadas cilíndricas obtenemos:

a)

∫02π∫02∫r24  r2senθ dzdrdθ\int_0^{2\pi}\int_0^2\int_{r^2}^4\ \ r^2sen\theta\ dzdrd\theta  

b)

∫02π∫02∫r24  r2cos⁡θ dzdrdθ\int_0^{2\pi}\int_0^2\int_{r^2}^4\ \ r^2\cos\theta\ dzdrd\theta  

c)

∫02∫02π∫r24  r2cos⁡θ dzdrdθ\int_0^2\int_0^{2\pi}\int_{r^2}^4\ \ r^2\cos\theta\ dzdrd\theta  

d)

∫02π∫02∫r24  r2cos⁡θ dzdθdr\int_0^{2\pi}\int_0^2\int_{r^2}^4\ \ r^2\cos\theta\ dzd\theta dr  

46.

Describir la región dada en coordenadas esféricas

a)

E={0≤θ≤2π; 0≤ϕ≤π2; 9≤ρ≤25}E=\left\{0\le\theta\le2\pi;\ 0\le\phi\le\frac{\pi}{2};\ 9\le\rho\le25\right\}

b)

E={0≤θ≤2π; 0≤ϕ≤π4; 3≤ρ≤5}E=\left\{0\le\theta\le2\pi;\ 0\le\phi\le\frac{\pi}{4};\ 3\le\rho\le5\right\}

c)

E={0≤θ≤2π; 0≤ϕ≤π3; 3≤ρ≤5}E=\left\{0\le\theta\le2\pi;\ 0\le\phi\le\frac{\pi}{3};\ 3\le\rho\le5\right\}

47.

 Se tiene el sólido E encerrada por las superficies  S1: z=8−x2−y2   ;   S2: z =x2+y2S_1:\ z=\sqrt{8-x^2-y^2\ }\ \ ;\ \ \ S_2:\ z\ =\sqrt{x^2+y^2} . La descripción del solido en coordenadas esféricas es::

a)

E={0≤θ≤2π; 0≤ϕ≤π4; 0≤ρ≤8}E=\left\{0\le\theta\le2\pi;\ 0\le\phi\le\frac{\pi}{4};\ 0\le\rho\le\sqrt{8}\right\}  

b)

E={0≤θ≤2π; 0≤ϕ≤π2; 0≤ρ≤8}E=\left\{0\le\theta\le2\pi;\ 0\le\phi\le\frac{\pi}{2};\ 0\le\rho\le8\right\}  

c)

E={0≤θ≤π2; 0≤ϕ≤π2; 0≤ρ≤8}E=\left\{0\le\theta\le\frac{\pi}{2};\ 0\le\phi\le\frac{\pi}{2};\ 0\le\rho\le8\right\}  

48.

Find the cylindrical coordinate for the Cartesian coordinate

 (x,y,z)=(1,−1, 3).\left(x,y,z\right)=\left(1,-1,\ 3\right).  

a)

 (2,π4,3)\left(\sqrt{2},\frac{\pi}{4},3\right)  

b)

 (2,−π4,3)\left(\sqrt{2},-\frac{\pi}{4},3\right)  

c)

 (11,π4,3)\left(\sqrt{11},\frac{\pi}{4},3\right)  

d)

 (11,−π4,3)\left(\sqrt{11},-\frac{\pi}{4},3\right)  

49.

Set up the limit of triple integral to find the volume of the solid bounded by  z=4−x2z=4-x^2  ,  y+z=5 ,z=0, y=0y+z=5\ ,z=0,\ y=0  

a)
b)
c)
d)
50.

Evaluate the triple integral

∫∫∫E6xy dV\int\int\int_E6xy\ dV where EE lies under the plane z=1+x+yz=1+x+y and above the region in the xy-plane bounded by the curves y=x , y=0, x=1y=\sqrt{x\ },\ y=0,\ x=1 . The result is equal to (a)   (Please write in a fraction term a/b)

51.

Calculate the value of the multiple integral ∫∫D(x2+y2)32dA\int_{ }^{ }\int_D^{ }\left(x^2+y^2\right)^{\frac{3}{2}}dA , where DD is the region in the first quadrant bounded by the lines y=0y=0 and y=3xy=\sqrt[]{3}x and the circle x2+y2=9x^2+y^2=9 . The result is equal to___

a)

81π5\frac{81\pi}{5}

b)

27π5\frac{27\pi}{5}

c)

9π5\frac{9\pi}{5}

d)

3π5\frac{3\pi}{5}

52.

Is it TRUE or FALSE:

∫−12∫05x2sin⁡(x−y)dxdy=∫05∫−12x2sin⁡(x−y)dydx\int_{-1}^2\int_0^5x^2\sin\left(x-y\right)dxdy=\int_0^5\int_{-1}^2x^2\sin\left(x-y\right)dydx

a)

TRUE

b)

FALSE

53.

What is the formula for calculating the volume of a solid using a triple integral?

a)

∭∭∭ f(x, y, z) dV

b)

∬∬∬ f(x, y, z) dV

c)

∭∭ f(x, y, z) dV

d)

∫∫∫ f(x, y, z) dV

54.

What is the concept of iterated integrals?

a)

A mathematical concept used to calculate multiple integrals by breaking the region into smaller pieces and integrating over each piece.

b)

A cooking technique used to prepare multiple dishes simultaneously

c)

A concept in computer programming for repeating a sequence of instructions

d)

A method for solving algebraic equations using repeated addition

55.

How do you determine the limits of integration for a double integral?

a)

Guess randomly

b)

Consider the region of integration and the bounds of the variables involved.

c)

Use the value of the function at a single point

d)

Ask someone else to determine the limits

56.

Calcula el área bajo la curva

y=8x(x2−1)10y=8x\left(x^2-1\right)^{10}  comprendida entre x=0 y x=1.

a)

411u2\frac{4}{11}u^2  

b)

−25u2-\frac{2}{5}u^2  

c)

−811u2-\frac{8}{11}u^2  

d)

25u2\frac{2}{5}u^2  

57.

Determine el valor de la integral que se muestra en la imagen

a)

200

b)

49

c)

15

d)

175

58.

Responder: ¿Qué es un integral definida?

a)

Una función

b)

Una antiderivada

c)

Un diferencial

d)

Un límite de sumas

59.

El valor de la integral ∫−11x3dx\int_{-1}^1x^3dx   es:

a)

Positivo

b)

Negativo

c)

Cero

d)

No se puede determinar

60.
a)

10.510.5  

b)

2121  

c)

1111  

d)

12.512.5  

61.

Una suma de Riemann que permite calcular la integral ∫12(3x2−2x)dx\int_1^2\left(3x^2-2x\right)dx es:

a)

lim⁡n→∞∑k=1∞(3 k2n2−2 kn) 1n\lim_{n\rightarrow\infty}\sum_{k=1}^{\infty}\left(3\ \frac{k^2}{n^2}-2\ \frac{k}{n}\right)\ \frac{1}{n}  

b)

lim⁡n→∞∑k=1∞(1n+4 kn2+3 k2 n3)\lim_{n\rightarrow\infty}\sum_{k=1}^{\infty}\left(\frac{1}{n}+4\ \frac{k}{n^2}+3\ \frac{k^{2\ }}{n^3}\right)  

c)

lim⁡n→∞∑k=1∞(3 (1+kn)2+2 (1+kn)) 1n\lim_{n\rightarrow\infty}\sum_{k=1}^{\infty}\left(3\ \left(1+\frac{k}{n}\right)^2+2\ \left(1+\frac{k}{n}\right)\right)\ \frac{1}{n}  

d)

Ninguna de las anteriores