WorksheetsDaily Challenge 1: Odd-and-Even and Cofunction Identities
Total questions: 10
Worksheet time: 15mins
Consider the function f(x)=sin−1x .
Which of the following is true?
f(−x)=f(x)
even function
f(−x)=−f(x)
odd function
neither odd nor even function
Consider the function f(x)=tan−1x .
Which of the following is true?
f(−x)=f(x)
even function
f(−x)=−f(x)
odd function
neither odd nor even function
Consider the function f(x)=cos−1x .
Which of the following is true?
f(−x)=f(x)
even function
f(−x)=−f(x)
odd function
neither odd nor even function
What are the colors of the graphs of y=sin−1x and y=tan−1x ?
red and blue
green and blue
red and green
The graphs of y=sin−1x and y=tan−1x are
symmetric with respect to the x-axis
symmetric with respect to the y-axis
symmetric with respect to the origin
not symmetric
The graph of y=cos−1x is
symmetric with respect to the x-axis
symmetric with respect to the y-axis
symmetric with respect to the origin
not symmetric
The graph of y=sinx can be described as the graph of y=cosx shifted
2π to the right
2π to the left
π to the right
π to the left
This means we can describe sine as
sinx=cos(x+2π)
sinx=cos(x−2π)
sinx=cos(x+π)
sinx=cos(x−π)
Since
sine is an odd function
sine is an even function
cosine is an odd function
cosine is an even function
We can derive the Cofunction Identity
sin(2π−x)=cosx
cos(2π−x)=sinx
sin(2π+x)=cosx
cos(2π+x)=sinx
