Free Printable Alg 1 HW 5-21-25. Review Day 2 on Quadratics Unit Test.

Worksheets

Alg 1 HW 5-21-25. Review Day 2 on Quadratics Unit Test.

Total questions: 15

Worksheet time: 4hrs 45mins

Name

Class

Date

A ball was projected from a height (in feet) and it followed the parabola path above. (click to enlarge the picture).

a) What is the starting (initial) height of the ball when it was thrown? (a)

b) Where did you find this information? (b)

c) At what time(s) did the ball hit the ground? (c)

d) Where did you find this information? (d)

Choose from the below words

10 feet

4 feet

4.5 feet

9 seconds

4.5 seconds

3 seconds

At the y-intercept

At the x-intercept

At the vertex

At the line of symmetry

A ball was projected from a height (in feet) and it followed the parabola path above. (click to enlarge the picture).

a) What is the maximum (highest) height of the ball? (a)

b) How long did it take the ball to reach the maximum? (b)

c) Where did you find the information above? (c)

Choose from the below words

Exactly 12 feet

12.5 feet

4 seconds

5 second

3 seconds

At the vertex

At the x-intercept

At the y-intercept

A ball was projected from a height (in feet) and it followed the parabola path above. (click to enlarge the picture).

a) What is the height of the ball after 2 seconds? (a)

b) What is the height of the ball after 3 seconds? (b)

c) At what time(s) was the ball at 8 feet above the ground? (c)

Choose from the below words

5 feet

4 feet

10.5 feet

1 second & 7 seconds

2 second & 6 seconds

1 second only

12 feet

4.5 feet

7 seconds only

The parabola shows the trajectory of a diver as he dived into the sea (Click the picture to enlarge it)

a) What is his position after 4 seconds? (a)

b) At what two times was he 3 feet below the ground? (b)

c) What is his position after 12 seconds? (c)

Choose from the below words

3 feet below the ground

5 feet above the ground

0 feet above the ground

4 seconds

3 seconds

5 feet below the ground

Still at the ground level.

4 seconds and 8 seconds

3 seconds and 7 seconds

The parabola shows the trajectory of a diver as he dived into the sea (Click the picture to enlarge it)

a) What is his starting height before diving? (a)

b) Where did you find this information? (b)

c) What time was he back at ground level after completing diving? (c)

d) Where did you find the information? (d)

Choose from the below words

5 feet above the ground

4 feet above the ground

0 feet above the ground

10 seconds

6 seconds

8 seconds

At the y-intercept

At the x-intercept

At the vertex

The parabola shows the trajectory of a diver as he dived into the sea (Click the picture to enlarge it)

a) What is his minimum (lowest) point before turning? (a)

b) What time was he at the lowest (minimum) point? (b)

c) Where did you find the information? (c)

Choose from the below words

6 feet below the ground

4 feet below the ground

4 feet above the ground

4 seconds

2 seconds

6 seconds

At the vertex

At the x-intercept

At the y-intercept

The profit of a new item is modelled as shown such that the profit increases up to a certain price and then start to decrease after that price (Click the picture to enlarge it)

a) What is the maximum (highest) profit generated? (a)

b) What price per item yields maximum profit? (b)

c) Where did you find the information above? (c)

d) As the company advisor, what price per item will you advise them to sell? (d)

Choose from the below words

About $10.00,

$3 per item

$4 per item

$18

$6 per item

At the x-intercepts

At the y-intercept

At the vertex

$24

$8 per item

To minimize the cost, a small business owner plans to follow the model above showing how the cost varies with number of items purchased.

a) What is the starting cost? (a)

b) Where did you find the information? (b)

c) How many items yields $14 cost? (c)

Choose from the below words

$14

Both 0 item and 12 items

2 and 5 items

10 items

$12

At the y-intercept.

Change the quadratic equation from factored form to standard form:

y= (x + 3)(x - 2)

y =

x² + 6x + 5

x² -5x + 6

6x²+ 6

x² + x - 6

10.

Write in standard form:

$f\left(x\right)\ =\ \left(2x-1\right)\left(3x+4\right)$

f(x) =

$6x^2-5x-4$

$6x^2+5x-4$

$6x+11x+4$

$6x+5x-4$

$6x^2-11x-4$

11.

Write in standard form:

$f\left(x\right)\ =\ \left(x-1\right)^2+5$
f(x) =

x² - x + 2

x² - 2x - 5

x² - 2x + 6

x² - 2x + 5

12.

Write in Factored form using diamond and slide / divide.
x² + 11x + 24

a) a⋅c= (a)

b) b = (b)

c) So, x² + 11x + 24 = (c)

Choose from the below words

(x + 6)(x + 4)

(x + 10)(x + 2)

(x + 2)(x + 12)

(x + 8)(x + 3)

-11

13.

Write in Factored form using diamond and slide / divide.
y= x² - 8x + 15

a) a⋅c = (a)

b) b = (b)

So, x² - 8x + 15 = (c)

Choose from the below words

(x + 5) ( x + 3)

(x + 15) (x - 1)

(x - 7) (x - 8)

-8

(x-5)(x-3)

-15

14.

Find the x-intercepts (zeros). Use to write the function in factored form.

X-intercepts: (a)

The Factored form: (b)

Find the vertex. Use to write the function in vertex form.

Vertex: (c)

The Vertex form: (d)

Choose from the below words

y= (x+4)(x+2)

y=(x-4)(x-2)

y = (x + 4)(x - 2)

y = (x+3)2 - 1

y = (x-3)2-1

x=-4 and x=-2

(-3, -1)

(3, 1)

15.

Find the vertex, use to write the equation in vertex form

Vertex = (a)

The Vertex form: (b)

Find the x-intercepts (zeros). Use to write the function in factored form.

x intercepts: (c)

Factored form: (d)

Choose from the below words

x=-4, x = 2

(3, -1)

x=-3

y=(x+3)2 - 1

(3,1)

y= -(x-3)2 + 1

x=2, x=4

y = - (x -2) (x -4)

y = (x + 2) (x + 4)

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Alg 1 HW 5-21-25. Review Day 2 on Quadratics Unit Test.

Total questions: 15

Worksheet time: 4hrs 45mins

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