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Day 68-Dec 2-worksheet-PWD-Rivet & welded connecttions

Total questions: 15

Worksheet time: 11mins

Name
Class
Date
1.

In a fillet weld, the effective throat thickness Te is calculated as.

a)

Te=skTe = \dfrac{s}{k}

b)

Te=k×sTe = k \times s

c)

Te=s2×kTe = s^2 \times k

d)

Te=ksTe = \dfrac{k}{s}

2.

Deep penetration fillet welds are defined when penetration beyond the root is.

a)

< 1.0 mm

b)

< 1.8 mm

c)

< 2.4 mm

d)

≥ 2.4 mm

3.

For field welds, the partial safety factor ymv is.

a)

1.10

b)

1.15

c)

1.25

d)

1.50

4.

Minimum pitch for rivets in both chain and zig‑zag riveting is.

a)

2d2d

b)

2.5d2.5d

c)

3.5d3.5d

d)

1.5d1.5d

5.

In butt weld design, reinforcement thickness is.

a)

Always considered in design

b)

Neglected in design

c)

Equal to effective throat

d)

Half of plate thickness

6.

For standard fillet welds, the ratio Te : s is.

a)

1 : 1

b)

1 : 1.41

c)

1 : 2\sqrt{2}

d)

2\sqrt{2} : 1

7.

Gauge distance in riveted joints is also known as.

a)

Row pitch

b)

Edge pitch

c)

Diagonal pitch

d)

Effective pitch

8.

TRUE / FALSE: The maximum size of a fillet weld with a square edge is plate thickness minus 1.5 mm.

a)

True

b)

False

9.

ASSERTION–REASON: Assertion (A): Reinforcement increases the static load strength of butt welds. Reason (R): The reinforcement increases the effective throat thickness considered for design. Choose the correct alternative.

a)

Both A and R true, R explains A

b)

Both A and R true, R does NOT explain A

c)

A true but R false

d)

A false but R true

10.

FILL IN THE BLANKS: The size of a normal fillet weld is the minimum (a)   of the fillet weld.

11.

FILL IN THE BLANKS: Effective length of a fillet weld = Actual length − (a)   .

12.

FILL IN THE BLANKS: In welded joints, the critical stress in a fillet weld is (a)   stress.

13.

NUMERICALS: A fillet weld has a leg size s = 8 mm and fusion surface angle 100°. Given k = 0.65. Find the effective throat thickness.

(a)  

14.

A 22 mm rivet is used. Find hole diameter.

(a)  

15.

Rivet in single shear with hole diameter = 21 mm and allowable shear stress τ=100 N/mm2\tau = 100\ \text{N/mm}^2 . Find shear capacity.

(a)