Exponential Growth and Decay

Front

The value of a car is $15,000 and depreciates at a rate of 8% per year. What is the decay factor?

Back

.92

Front

Function with initial amount $15 and 35% increase each year: y = 15(35)^x, y = 15(1.35)^x, y = 15(0.35)^x, y = 35(1.15)^x

Back

y = 15(1.35)^x

Front

Classify the model: A=1200(.85)⁶
Options: Growth, Decay

Back

Decay

Front

Classify the model: A=10(1.01)³
Options: Growth, Decay

Back

Growth

Front

What type of function is y = 7(5/4)^x? Options: Exponential Growth, Exponential Decay, Linear, None of the above

Back

Exponential Growth

Front

Write an equation that models the following situation:
Samantha's hair was known to grow very rapidly. It began at a length of 6 in and grew at a rate of 14% a week.
Options: y=6(0.14)^x, y=6(1+14)^x, y=6(1.14)^x, y=6(0.86)^x

Back

y=6(1.14)^x

Front

Equation for bacteria culture starting with 5000 cells, dying by 30% each year.

Back

y=5000(0.7)^x

Front

A population of fish starts at 8,000 and decreases by 6% per year. What is the population of fish after 10 years?

Back

4309

Front

Daniel’s Print Shop purchased a new printer for $35,000. Each year it depreciates at a rate of 5%. How much will the printer be worth in 8 years?

Back

$23,219.72

Front

The number of mosquitoes at the beginning of the summer was 4,000. The population of mosquitoes is expected to grow at a rate of 25% a month. How many mosquitoes will there be after 4 months?

Back

To find the number of mosquitoes after 4 months, we can use the formula: $P = P_0(1 + r)^t$, where $P_0$ is the initial population, $r$ is the growth rate, and $t$ is the time in months. Here, $P_0 = 4000$, $r = 0.25$, and $t = 4$. Thus, $P = 4000(1 + 0.25)^4 = 4000(1.25)^4 = 4000(2.44140625) \approx 9765$.