Standard, Slope-Intercept, Point-Slope Form

Front

Which of these represents point-slope form of a linear equation? Options: y - y₁ = m(x - x₁), Ax + By = C, y = mx + b, y=kx

Back

y - y₁ = m(x - x₁)

Front

Which of these represents slope-intercept form of a linear equation? Options: y - y₁ = m(x-x₁), Ax + By = C, y = mx + b, y=kx

Back

y = mx + b

Front

Which of these represents standard form of a linear equation? Options: y - y₁ = m(x-x₁), Ax + By = C, y = mx + b, y=kx

Back

Ax + By = C

Front

Write the equation in point-slope form for the line that contains the points (-2, -3), (4, 3)

Back

y + 3 = 1(x + 2)

Front

Back

Front

Which is NOT a correct point-slope equation for the line in #14? Options: y - 0 = 1/2(x + 2), y - 1 = 1/2(x - 0), y + 2 = 1/2(x + 2), y - 2 = 1/2(x - 2)

Back

y + 2 = 1/2(x + 2)

Front

Convert y=3/7x-1 to standard form.

Back

3x-7y=7

Front

Find the x and y intercepts
4x - 5y = 40

Back

x intercept is 10
y intercept is -8

Front

What type of slope does the graph have? Options: Positive, Negative, Zero Slope, Undefined

Back

Undefined

Front

What is the standard form of
y - 7 = -2/3(x + 1)?

Back

2x + 3y = 19