Solving Quadratics by Factoring

Front

Solve for the values of x:
(x - 3)(x + 6) = 0

Back

{ 3, -6 }

Front

What is the first step in solving (x + 2)(x - 3) = 0?

Back

Set each binomial factor equal to zero

Front

Solve: k² - 2k - 24 = 0

Back

k = -4, 6

Front

Solve: 3x² + 18x +15 = 0

Back

x = -5, -1

Front

Solve
x² + 2x - 24 = 0

Back

x = -6, x = 4

Front

Solve
x² + 9x + 20 = 0

Back

x = -4, x = -5

Front

Solve
x² + 7x + 12 = 0

Back

x = -3, x = -4

Front

Solve
x² + 13x + 12 = 0

Back

x = -1, x = -12

Front

x² +0x - 49 = 0

Back

x = -7, x = 7

Front

Solve by factoring: x² - 9x + 20 = 0

Back

x = 4 and x = 5