Transformations of functions Review

Front

If the blue function is f(x)=x², then the red function must be? Options: g(x)=x²-5, g(x)=x²+5, g(x)=(x-5)², g(x)=(x+5)²

Back

g(x)=x²-5

Front

Transformation of y = |x - 4| from y = |x|

Back

Right 4

Front

Equation of the graph: f(x ) = I x + 4 I + 2, f(x ) = -I x - 4 I + 2, f(x ) = I x - 4 I + 2, f(x ) = -I x + 4 I + 2

Back

f(x ) = -I x + 4 I + 2

Tags

CCSS.HSF-IF.C.7D

Front

Transformations from the parent graph to f(x) = -3∣x + 5∣ - 7

Back

Down 7, Left 5, Vertical Stretch by 3, Reflection across x-axis

Front

Write an absolute value function given the following transformations: Reflection across the x-axis, Translates right 2 units and 7 units down.

Back

y = -|x - 2| - 7

Front

Write an absolute value function given the following transformations: Vertical Stretch by a factor of 2, Translates left 1 unit and 9 units down. Options: f(x) = |2x + 1| - 9, f(x) = |2x - 1| - 9, f(x) = 2|x + 1| - 9, f(x) = 2|x - 1| - 9, None of these are correct.

Back

f(x) = 2|x + 1| - 9

Front

Describe the translation of y = x² + 4

Back

translate UP 4 units

Front

Compare the function y = 0.3x² to the parent function y = x². Options: Vertical Stretch, Vertical Compression, Translation left, Translation up

Back

Vertical Compression

Front

Match the equation to its description: Reflected over x, right 2 and up 1, Reflected over x, left 2 and up 1, Reflected over x, right 2 and down 1, Reflected over x, left 2 and down 1

Back

Reflected over x, right 2 and up 1

Front

If the blue is f(x)=x², the red must be: g(x)=(x+3)², g(x)=(x-3)², g(x)=x²+3, g(x)=x²-2

Back

g(x)=(x-3)²