

SohCahToa, Special Right Triangles, Incenter and Circumcenter
Flashcard
•
Mathematics
•
10th Grade
•
Practice Problem
•
Hard
Wayground Content
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15 questions
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1.
FLASHCARD QUESTION
Front
What does SohCahToa stand for in trigonometry?
Back
SohCahToa is a mnemonic for the definitions of the sine, cosine, and tangent functions: Sine = Opposite/Hypotenuse, Cosine = Adjacent/Hypotenuse, Tangent = Opposite/Adjacent.
2.
FLASHCARD QUESTION
Front
What are the special right triangles and their angle measures?
Back
The special right triangles are the 45-45-90 triangle and the 30-60-90 triangle. In a 45-45-90 triangle, the angles are 45°, 45°, and 90°, and the sides are in the ratio 1:1:√2. In a 30-60-90 triangle, the angles are 30°, 60°, and 90°, and the sides are in the ratio 1:√3:2.
3.
FLASHCARD QUESTION
Front
What is the definition of the incenter of a triangle?
Back
The incenter of a triangle is the point where the angle bisectors of the triangle intersect. It is also the center of the circle inscribed within the triangle.
4.
FLASHCARD QUESTION
Front
How do you find the length of the hypotenuse in a right triangle?
Back
To find the length of the hypotenuse in a right triangle, you can use the Pythagorean theorem: a² + b² = c², where c is the length of the hypotenuse and a and b are the lengths of the other two sides.
5.
FLASHCARD QUESTION
Front
What is the circumcenter of a triangle?
Back
The circumcenter of a triangle is the point where the perpendicular bisectors of the sides of the triangle intersect. It is the center of the circle that passes through all three vertices of the triangle.
6.
FLASHCARD QUESTION
Front
What is the relationship between the sides of a 30-60-90 triangle?
Back
In a 30-60-90 triangle, the lengths of the sides are in the ratio 1:√3:2, where the side opposite the 30° angle is 1, the side opposite the 60° angle is √3, and the hypotenuse is 2.
7.
FLASHCARD QUESTION
Front
What is the formula for the area of a triangle using the inradius?
Back
The area of a triangle can be calculated using the formula: Area = r * s, where r is the inradius and s is the semi-perimeter of the triangle.
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