General Math TMSCA 1

General Math TMSCA 1

Assessment

Flashcard

Mathematics

7th - 8th Grade

Practice Problem

Hard

CCSS
6.EE.A.1, 4.MD.A.1, 6.NS.B.3

+5

Standards-aligned

Created by

Wayground Content

FREE Resource

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16 questions

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1.

FLASHCARD QUESTION

Front

What is the process to find the number of items donated per charity when given a total and number of charities?

Back

To find the number of items donated per charity, divide the total number of items by the number of charities. For example, if Bob has 91 pairs of socks and donates to 7 charities, the calculation is 91 ÷ 7 = 13 pairs per charity.

Tags

CCSS.6.RP.A.1

CCSS.6.RP.A.2

2.

FLASHCARD QUESTION

Front

What is 9 raised to the power of 3?

Back

9 raised to the power of 3 (9^3) is calculated as 9 x 9 x 9, which equals 729.

Tags

CCSS.6.EE.A.1

3.

FLASHCARD QUESTION

Front

How do you simplify a fraction?

Back

To simplify a fraction, divide the numerator and the denominator by their greatest common divisor (GCD). For example, to simplify 8/12, the GCD is 4, so 8 ÷ 4 = 2 and 12 ÷ 4 = 3, resulting in 2/3.

4.

FLASHCARD QUESTION

Front

How many ounces are in one cup?

Back

There are 8 ounces in one cup. Therefore, in three cups, there are 3 x 8 = 24 ounces.

Tags

CCSS.4.MD.A.1

5.

FLASHCARD QUESTION

Front

How do you calculate the total cost of items when given the cost per item and the quantity?

Back

To calculate the total cost, multiply the cost per item by the quantity. For example, if each paperclip costs $0.01 and Ms. Johnson buys 62 paperclips, the total cost is 0.01 x 62 = $0.62.

Tags

CCSS.6.NS.B.3

6.

FLASHCARD QUESTION

Front

What is the formula for calculating the average donation per charity?

Back

The average donation per charity can be calculated using the formula: Average = Total Donations ÷ Number of Charities.

7.

FLASHCARD QUESTION

Front

What is the significance of the greatest common divisor (GCD) in fraction simplification?

Back

The GCD is significant in fraction simplification because it allows you to reduce the fraction to its simplest form, making it easier to understand and work with.

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