MVT Flashcard

MVT Flashcard

Assessment

Flashcard

Mathematics

12th Grade

Hard

CCSS
HSF-IF.C.7D, 8.F.B.4, HSF.IF.B.6

Standards-aligned

Created by

Wayground Content

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15 questions

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1.

FLASHCARD QUESTION

Front

What is the Mean Value Theorem (MVT)?

Back

The Mean Value Theorem states that if a function f is continuous on the closed interval [a, b] and differentiable on the open interval (a, b), then there exists at least one c in (a, b) such that f'(c) = (f(b) - f(a)) / (b - a).

2.

FLASHCARD QUESTION

Front

What are the conditions required for the Mean Value Theorem to apply?

Back

The function must be continuous on a closed interval [a, b] and differentiable on the open interval (a, b).

3.

FLASHCARD QUESTION

Front

How do you find the value of c in the Mean Value Theorem?

Back

To find c, you need to calculate the average rate of change of the function over the interval [a, b] and then solve the equation f'(c) = (f(b) - f(a)) / (b - a).

4.

FLASHCARD QUESTION

Front

What is the Extreme Value Theorem?

Back

The Extreme Value Theorem states that if a function is continuous on a closed interval [a, b], then it attains both a maximum and a minimum value at some points in that interval.

5.

FLASHCARD QUESTION

Front

What is a discontinuous function?

Back

A discontinuous function is one that is not continuous at one or more points in its domain, meaning there are breaks, jumps, or asymptotes in the graph.

Tags

CCSS.HSF-IF.C.7D

6.

FLASHCARD QUESTION

Front

Give an example of a function that is discontinuous on the interval [-1, 1].

Back

An example is y = log(x), which is undefined for x ≤ 0, making it discontinuous on the interval [-1, 1].

7.

FLASHCARD QUESTION

Front

What does it mean for a function to be continuous on an interval?

Back

A function is continuous on an interval if there are no breaks, jumps, or holes in the graph of the function over that interval.

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