CA Unit 3 Multiplying Radicals
Flashcard
•
Mathematics
•
11th Grade
•
Practice Problem
•
Hard
Standards-aligned
Wayground Content
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15 questions
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1.
FLASHCARD QUESTION
Front
What is the product of two radicals, \(\sqrt{a} \cdot \sqrt{b}\)?
Back
The product of two radicals is \(\sqrt{a} \cdot \sqrt{b} = \sqrt{a \cdot b}\).
2.
FLASHCARD QUESTION
Front
How do you simplify the expression \(\sqrt{a} \cdot \sqrt{b} \cdot \sqrt{c}\)?
Back
You can simplify it as \(\sqrt{a} \cdot \sqrt{b} \cdot \sqrt{c} = \sqrt{a \cdot b \cdot c}\).
3.
FLASHCARD QUESTION
Front
What is the distributive property in the context of multiplying binomials?
Back
The distributive property states that \(a(b + c) = ab + ac\). This applies to multiplying binomials as well.
Tags
CCSS.HSA.APR.A.1
4.
FLASHCARD QUESTION
Front
How do you multiply two binomials that contain radicals, such as \((a + b)(c + d)\)?
Back
You apply the distributive property: \((a + b)(c + d) = ac + ad + bc + bd\).
5.
FLASHCARD QUESTION
Front
What is the result of multiplying \(\left(4\sqrt{2}-2\sqrt{3}\right)\left(5\sqrt{2}-\sqrt{3}\right)?
Back
The result is \(46 - 14\sqrt{6}\).
Tags
CCSS.HSN.RN.A.2
6.
FLASHCARD QUESTION
Front
How do you simplify the expression \(-2\sqrt{10} \left(\sqrt{3} - 4\sqrt{2}\right)?
Back
Distributing gives \(-2\sqrt{10} \cdot \sqrt{3} + 8\sqrt{20} = -2\sqrt{30} + 16\sqrt{5}\).
Tags
CCSS.HSN.RN.A.2
7.
FLASHCARD QUESTION
Front
What is the product of \(-2\sqrt{7}\) and \(3\sqrt{28}\)?
Back
The product is \(-84\).
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