
AMP Units 4-5 Review FY25
Flashcard
•
Mathematics
•
6th Grade
•
Practice Problem
•
Hard
Wayground Content
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15 questions
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1.
FLASHCARD QUESTION
Front
What is the process for simplifying the expression \(\frac{2}{3}(2x + 6) - 4\)?
Back
To simplify the expression, distribute \(\frac{2}{3}\) to both terms inside the parentheses: \(\frac{2}{3} \cdot 2x + \frac{2}{3} \cdot 6 - 4 = \frac{4x}{3} + 4 - 4 = \frac{4x}{3}\).
2.
FLASHCARD QUESTION
Front
How do you determine if two fractions are equivalent?
Back
Two fractions are equivalent if their cross products are equal, or if they simplify to the same lowest terms.
3.
FLASHCARD QUESTION
Front
What is the least common multiple (LCM) of two numbers, and how is it calculated?
Back
The least common multiple of two numbers is the smallest multiple that is evenly divisible by both numbers. It can be calculated by listing the multiples of each number and finding the smallest common one, or by using the formula: \(\text{LCM}(a, b) = \frac{|a \cdot b|}{\text{GCD}(a, b)}\).
4.
FLASHCARD QUESTION
Front
What is prime factorization, and how is it performed?
Back
Prime factorization is the process of expressing a number as the product of its prime factors. It is performed by dividing the number by the smallest prime number until the result is 1.
5.
FLASHCARD QUESTION
Front
What is the formula for finding the total cost of multiple items?
Back
The total cost can be found using the formula: \(\text{Total Cost} = \text{Number of Items} \times \text{Cost per Item}\).
6.
FLASHCARD QUESTION
Front
How do you simplify the expression \(\frac{6}{4}(-6x + 6) + 3x\)?
Back
First, distribute \(\frac{6}{4}\) to both terms: \(\frac{6}{4} \cdot -6x + \frac{6}{4} \cdot 6 + 3x = -\frac{36x}{4} + \frac{36}{4} + 3x = -9x + 9 + 3x = -6x + 9\).
7.
FLASHCARD QUESTION
Front
What is the significance of the greatest common divisor (GCD) in simplifying fractions?
Back
The greatest common divisor is used to simplify fractions by dividing both the numerator and the denominator by the GCD, resulting in the simplest form of the fraction.
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