Mid-unit 3 Review

Mid-unit 3 Review

Assessment

Flashcard

Mathematics

6th - 7th Grade

Hard

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15 questions

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1.

FLASHCARD QUESTION

Front

What is the formula to find the unit rate?

Back

The unit rate is found by dividing the total quantity by the number of units. For example, if you earned $200 for 8 hours of work, the unit rate is $200 ÷ 8 hours = $25 per hour.

2.

FLASHCARD QUESTION

Front

How do you calculate the ratio of a part to the whole?

Back

To calculate the ratio of a part to the whole, divide the number of parts by the total number of items. For example, if there are 3 red marbles out of 10 total marbles, the ratio is 3:10.

3.

FLASHCARD QUESTION

Front

What is the relationship between cups of flour and the number of cookies made?

Back

The relationship is a direct proportion. If 3 cups of flour make 60 cookies, then to find how many cups are needed for 90 cookies, set up a proportion: 3 cups/60 cookies = x cups/90 cookies.

4.

FLASHCARD QUESTION

Front

How do you find the price per gallon of gas?

Back

To find the price per gallon, divide the total cost by the number of gallons. For example, if it costs $46.80 to fill a 13-gallon tank, the price per gallon is $46.80 ÷ 13 gallons = $3.60.

5.

FLASHCARD QUESTION

Front

What is the process to convert a fraction to a unit rate?

Back

To convert a fraction to a unit rate, divide the numerator by the denominator and then adjust for the time or unit. For example, if Sasha mows 3/8 of an acre in 3/4 of an hour, first find the rate per hour.

6.

FLASHCARD QUESTION

Front

What is a direct proportion?

Back

A direct proportion means that as one quantity increases, the other quantity increases at a constant rate. For example, if the number of cookies increases, the amount of flour needed also increases.

7.

FLASHCARD QUESTION

Front

How do you set up a proportion to solve for an unknown?

Back

To set up a proportion, create a fraction that represents the relationship between two quantities and set it equal to another fraction representing a similar relationship. Cross-multiply to solve for the unknown.

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