Search Header Logo
  1. Resource Library
  2. Math
  3. Calculus
  4. Derivatives Of Trigonometric Functions
  5. Inverse Trig Derivatives
Inverse Trig Derivatives

Inverse Trig Derivatives

Assessment

Flashcard

•

Mathematics

•

10th - 12th Grade

•

Practice Problem

•

Hard

•
CCSS
HSF-BF.B.4A

Standards-aligned

Created by

Wayground Content

FREE Resource

Student preview

quiz-placeholder

14 questions

Show all answers

1.

FLASHCARD QUESTION

Front

What is the derivative of the inverse sine function, \( \sin^{-1}(x) \)?

Back

The derivative is \( \frac{1}{\sqrt{1-x^2}} \) for \( -1 < x < 1 \).

2.

FLASHCARD QUESTION

Front

What is the derivative of the inverse cosine function, \( \cos^{-1}(x) \)?

Back

The derivative is \( -\frac{1}{\sqrt{1-x^2}} \) for \( -1 < x < 1 \).

3.

FLASHCARD QUESTION

Front

What is the derivative of the inverse tangent function, \( \tan^{-1}(x) \)?

Back

The derivative is \( \frac{1}{1+x^2} \) for all \( x \).

Tags

CCSS.HSF-BF.B.4A

4.

FLASHCARD QUESTION

Front

What is the derivative of the inverse cotangent function, \( \cot^{-1}(x) \)?

Back

The derivative is \( -\frac{1}{1+x^2} \) for all \( x \).

5.

FLASHCARD QUESTION

Front

What is the derivative of the inverse secant function, \( \sec^{-1}(x) \)?

Back

The derivative is \( \frac{1}{|x|\sqrt{x^2-1}} \) for \( |x| > 1 \).

6.

FLASHCARD QUESTION

Front

What is the derivative of the inverse cosecant function, \( \csc^{-1}(x) \)?

Back

The derivative is \( -\frac{1}{|x|\sqrt{x^2-1}} \) for \( |x| > 1 \).

7.

FLASHCARD QUESTION

Front

How do you find the derivative of a composite function involving inverse trigonometric functions?

Back

Use the chain rule along with the derivatives of the inverse functions.

Access all questions and much more by creating a free account

Create resources

Host any resource

Get auto-graded reports

Google

Continue with Google

Email

Continue with Email

Microsoft

Continue with Microsoft

or continue with

Facebook

Facebook

Apple

Apple

Others

Others

By signing up, you agree to our Terms of Service & Privacy Policy

Already have an account?