Surface Area of Rectangular and Triangular Prisms

Front

What is the formula for the surface area of a rectangular prism?

Back

Surface Area = 2(lw + lh + wh), where l = length, w = width, h = height.

Tags

CCSS.7.G.B.6

Front

What is the formula for the surface area of a triangular prism?

Back

Surface Area = bh + l1h + l2h + l3h, where b = base, h = height of the triangle, l1, l2, l3 = lengths of the triangular sides.

Tags

CCSS.7.G.B.6

Front

How do you calculate the surface area of a rectangular prism with length 5 yd, width 4 yd, and height 2 yd?

Back

Surface Area = 2(5*4 + 5*2 + 4*2) = 2(20 + 10 + 8) = 76 yd².

Tags

CCSS.7.G.B.6

Front

If a rectangular prism has a surface area of 40 yd², what could be its dimensions?

Back

Possible dimensions could be 2 yd x 5 yd x 4 yd.

Tags

CCSS.7.G.B.6

Front

What is the surface area of a rectangular prism with dimensions 3 ft, 4 ft, and 5 ft?

Back

Surface Area = 2(3*4 + 3*5 + 4*5) = 2(12 + 15 + 20) = 94 ft².

Tags

CCSS.7.G.B.6

Front

What is the height of a triangular prism if the base area is 12 m² and the surface area is 48 m²?

Back

Height = (Surface Area - base area) / (perimeter of the base) = (48 - 12) / perimeter.

Tags

CCSS.7.G.B.6

Front

What is the surface area of a triangular prism with a base of 6 m, height of 4 m, and slant heights of 5 m, 5 m, and 6 m?

Back

Surface Area = 12 + (5+5+6)*4 = 12 + 16 = 28 m².

Tags

CCSS.7.G.B.6

Front

What is the relationship between the dimensions of a prism and its surface area?

Back

Increasing any dimension (length, width, height) generally increases the surface area.

Tags

CCSS.7.G.B.6

Front

How do you find the surface area of a prism if you know the area of the base and the height?

Back

Surface Area = 2 * Base Area + Perimeter of Base * Height.

Tags

CCSS.7.G.B.6

Front

What is the surface area of a triangular prism with a base of 10 yd, height of 5 yd, and lateral sides of 8 yd each?

Back

Surface Area = (1/2 * base * height) + (perimeter of base * height) = (1/2 * 10 * 5) + (10 + 8 + 8) * 5 = 25 + 130 = 155 yd².

Tags

CCSS.7.G.B.6