

Review for Math 1111 Final Exam
Flashcard
•
Mathematics
•
University
•
Practice Problem
•
Hard
Wayground Content
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15 questions
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1.
FLASHCARD QUESTION
Front
What is the y-intercept of the function y=4^(x+1)?
Back
The y-intercept is the point where the graph intersects the y-axis. For the function y=4^(x+1), the y-intercept occurs when x=0, giving y=4^(0+1)=4. Thus, the y-intercept is (0,4).
2.
FLASHCARD QUESTION
Front
How do you solve the inequality |x + 4| - 8 > 2?
Back
To solve |x + 4| - 8 > 2, first isolate the absolute value: |x + 4| > 10. This leads to two cases: x + 4 > 10 or x + 4 < -10. Solving these gives x > 6 or x < -14.
3.
FLASHCARD QUESTION
Front
What is the domain of the function f(x) = 3x/(x+3)?
Back
The domain of a function is the set of all possible input values (x) that will not cause division by zero. For f(x) = 3x/(x+3), the denominator x+3 cannot be zero, so x cannot be -3. Therefore, the domain is (-∞, -3) ∪ (-3, ∞).
4.
FLASHCARD QUESTION
Front
How do you evaluate f(x) - g(x) for f(x) = 3x + 8 and g(x) = x + 8?
Back
To evaluate f(x) - g(x), subtract the two functions: f(x) - g(x) = (3x + 8) - (x + 8) = 3x + 8 - x - 8 = 2x.
5.
FLASHCARD QUESTION
Front
What is the maximum height of an object launched upward with the function s(t) = -16t^2 + 64t + 80?
Back
To find the maximum height, use the vertex formula t = -b/(2a) for the quadratic equation s(t). Here, a = -16 and b = 64. Thus, t = -64/(2*-16) = 2 seconds. Plugging t back into s(t) gives s(2) = -16(2^2) + 64(2) + 80 = 144 ft.
6.
FLASHCARD QUESTION
Front
What is the definition of a function?
Back
A function is a relation that assigns exactly one output (y) for each input (x). It can be represented as f(x), where x is the input and f(x) is the output.
7.
FLASHCARD QUESTION
Front
What does it mean for a function to be continuous?
Back
A function is continuous if there are no breaks, jumps, or holes in its graph. Formally, a function f is continuous at a point x=a if lim (x→a) f(x) = f(a).
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