
M1 Unit 1 Review
Flashcard
•
Mathematics
•
9th - 12th Grade
•
Practice Problem
•
Easy
Edward D Coleman
Used 1+ times
FREE Resource
Student preview

28 questions
Show all answers
1.
FLASHCARD QUESTION
Front
Back
5
Answer explanation
In the expression 5d + 2, the coefficient is the number that multiplies the variable. Here, 5 is the coefficient of d, making it the correct answer.
2.
FLASHCARD QUESTION
Front
Back
5d and 2
Answer explanation
In the expression 5d + 2, the terms are the distinct parts that are added together. Here, 5d and 2 are both separate terms, making '5d and 2' the correct choice.
3.
FLASHCARD QUESTION
Front
A letter that represents a number is called a _____.
Back
variable
Answer explanation
A letter that represents a number is called a variable. In mathematics, variables are used to denote unknown values, making them essential for algebraic expressions and equations.
4.
FLASHCARD QUESTION
Front
Back
Answer explanation
To solve for l in the equation V = lwh, divide both sides by wh. This gives l = V / (wh), which matches the correct answer choice.
5.
FLASHCARD QUESTION
Front
Back
Answer explanation
To solve for x in the equation ax - b = c, first add b to both sides: ax = c + b. Then, divide both sides by a to isolate x: x = (c + b) / a. Thus, the correct answer is x = (c + b) / a.
6.
FLASHCARD QUESTION
Front
An equation has ____________ when you simplify and the variable terms on each side are the same, BUT the constants are different.
Back
no solution
Answer explanation
An equation has no solution when the variable terms are the same on both sides, but the constants differ. This means there is no value for the variable that can satisfy the equation.
7.
FLASHCARD QUESTION
Front
An equation has ____________ when you simplify and the variable terms on each side are the same, AND the constants are the same.
Back
infinite solutions
Answer explanation
An equation has infinite solutions when the variable terms and constants on both sides are identical after simplification. This means any value for the variable will satisfy the equation, leading to infinitely many solutions.
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