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B2 Geometric Mean Review

B2 Geometric Mean Review

Assessment

Flashcard

•

Mathematics

•

9th - 12th Grade

•

Practice Problem

•

Hard

•
CCSS
8.EE.A.2

Standards-aligned

Created by

Wayground Content

FREE Resource

Student preview

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15 questions

Show all answers

1.

FLASHCARD QUESTION

Front

What is the geometric mean of two numbers?

Back

The geometric mean of two numbers a and b is defined as the square root of their product: Geometric Mean=GM=sqrt(a×b)\text{Geometric Mean} = \text{GM} = \text{sqrt}(a \times b) .

Tags

CCSS.8.EE.A.2

2.

FLASHCARD QUESTION

Front

Find the geometric mean between 64 and 25.

Back

The geometric mean is GM=sqrt(64×25)=sqrt(1600)=40\text{GM} = \text{sqrt}(64 \times 25) = \text{sqrt}(1600) = 40 .

Tags

CCSS.8.EE.A.2

3.

FLASHCARD QUESTION

Front

What is the formula to find the geometric mean of n numbers?

Back

The geometric mean of n numbers x1, x2, ..., xn is given by: GM=sqrt[n]x1×x2×...×xn\text{GM} = \text{sqrt[n]}{x_1 \times x_2 \times ... \times x_n} .

4.

FLASHCARD QUESTION

Front

If the geometric mean of two numbers is 6, what could the numbers be?

Back

Possible pairs could be (4, 9) since GM=sqrt(4×9)=6\text{GM} = \text{sqrt}(4 \times 9) = 6 .

Tags

CCSS.8.EE.A.2

5.

FLASHCARD QUESTION

Front

What is the geometric mean between 81 and 4?

Back

The geometric mean is GM=sqrt(81×4)=sqrt(324)=18\text{GM} = \text{sqrt}(81 \times 4) = \text{sqrt}(324) = 18 .

Tags

CCSS.8.EE.A.2

6.

FLASHCARD QUESTION

Front

Find x if the geometric mean of x and 16 is 8.

Back

Using the formula: GM=sqrt(x×16)=8\text{GM} = \text{sqrt}(x \times 16) = 8 , we find that x=4x = 4 .

Tags

CCSS.8.EE.A.2

7.

FLASHCARD QUESTION

Front

What is the geometric mean of 36 and 64?

Back

The geometric mean is GM=sqrt(36×64)=sqrt(2304)=48\text{GM} = \text{sqrt}(36 \times 64) = \text{sqrt}(2304) = 48 .

Tags

CCSS.8.EE.A.2

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