Pythagorean Theorem and Special Right Triangles

Pythagorean Theorem and Special Right Triangles

Assessment

Flashcard

Mathematics

9th - 12th Grade

Hard

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15 questions

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1.

FLASHCARD QUESTION

Front

What is the Pythagorean Theorem?

Back

The Pythagorean Theorem states that in a right triangle, the square of the length of the hypotenuse (c) is equal to the sum of the squares of the lengths of the other two sides (a and b). It can be expressed as: c² = a² + b².

2.

FLASHCARD QUESTION

Front

What are the special right triangles?

Back

The special right triangles are the 45-45-90 triangle and the 30-60-90 triangle. In a 45-45-90 triangle, the legs are equal, and the hypotenuse is √2 times the length of a leg. In a 30-60-90 triangle, the lengths of the sides are in the ratio 1:√3:2.

3.

FLASHCARD QUESTION

Front

How do you find the length of the hypotenuse in a right triangle?

Back

To find the length of the hypotenuse (c) in a right triangle, use the Pythagorean Theorem: c = √(a² + b²), where a and b are the lengths of the other two sides.

4.

FLASHCARD QUESTION

Front

What is the length of the legs in a 45-45-90 triangle if the hypotenuse is 10?

Back

In a 45-45-90 triangle, the legs are equal and can be found using the formula: leg = hypotenuse / √2. Therefore, if the hypotenuse is 10, each leg is 10/√2 = 5√2.

5.

FLASHCARD QUESTION

Front

What is the ratio of the sides in a 30-60-90 triangle?

Back

The ratio of the sides in a 30-60-90 triangle is 1:√3:2, where the side opposite the 30° angle is 1, the side opposite the 60° angle is √3, and the hypotenuse is 2.

6.

FLASHCARD QUESTION

Front

If one leg of a 30-60-90 triangle is 5, what is the length of the hypotenuse?

Back

In a 30-60-90 triangle, the hypotenuse is twice the length of the shorter leg. Therefore, if one leg is 5, the hypotenuse is 5 * 2 = 10.

7.

FLASHCARD QUESTION

Front

What is the value of x in a right triangle with legs of length 3 and 4?

Back

Using the Pythagorean Theorem: c² = 3² + 4² = 9 + 16 = 25. Therefore, x (the hypotenuse) = √25 = 5.

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