How do you solve for x in the equation $$x^2 = 36$$ ?

Take the square root of both sides: $$x = \text{sqrt}(36) = 6$$ or $$x = -6$$ .

Solve for z: $$z^2 = 117$$

$$z = \text{sqrt}(117) = 3\text{sqrt}(13)$$ .

Solve for z: $$z^2 = 396$$

$$z = \text{sqrt}(396) = 6\text{sqrt}(11)$$ .

What is the geometric mean of 2 and 8?

$$\text{Geometric Mean} = \text{sqrt}(2 \times 8) = \text{sqrt}(16) = 4$$ .

If $$x^2 = 20$$ , what is x?

$$x = \text{sqrt}(20) = 2\text{sqrt}(5)$$ .

What is the geometric mean of 1 and 25?

$$\text{Geometric Mean} = \text{sqrt}(1 \times 25) = \text{sqrt}(25) = 5$$ .

Solve for x: $$x^2 = 13$$

$$x = \text{sqrt}(13)$$ or $$x = -\text{sqrt}(13)$$ .

What is the geometric mean of 3 and 12?

$$\text{Geometric Mean} = \text{sqrt}(3 \times 12) = \text{sqrt}(36) = 6$$ .

If the geometric mean of two numbers is 10, what could the numbers be?

Possible pairs include (5, 20) since $$\text{sqrt}(5 \times 20) = 10$$ .

Solve for z: $$z^2 = 88$$

$$z = \text{sqrt}(88) = 2\text{sqrt}(22)$$ .

What is the geometric mean of 4 and 16?

$$\text{Geometric Mean} = \text{sqrt}(4 \times 16) = \text{sqrt}(64) = 8$$ .

3.8 Geometric Mean Practice

Flashcard

•

Mathematics

•

10th Grade

•

Practice Problem

•

Hard

•

CCSS

8.EE.A.2

Standards-aligned

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FLASHCARD QUESTION

Front

What is the geometric mean of two numbers a and b?

Back

Tags

CCSS.8.EE.A.2

FLASHCARD QUESTION

Front

Back

Tags

CCSS.8.EE.A.2

FLASHCARD QUESTION

Front

What is the formula for the geometric mean of n numbers?

Back

FLASHCARD QUESTION

Front

If the geometric mean of two numbers is 6, what could the numbers be?

Back

Tags

CCSS.8.EE.A.2

FLASHCARD QUESTION

Front

Back

Tags

CCSS.8.EE.A.2

FLASHCARD QUESTION

Front

What is the relationship between the arithmetic mean and geometric mean?

Back

The arithmetic mean is always greater than or equal to the geometric mean for non-negative numbers.

FLASHCARD QUESTION

Front

Back

Tags

CCSS.8.EE.A.2

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