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Multi-Step Equations (Variables on Both Sides)

Multi-Step Equations (Variables on Both Sides)

Assessment

Flashcard

•

Mathematics

•

6th Grade

•

Practice Problem

•

Easy

Created by

Wayground Content

Used 1+ times

FREE Resource

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16 questions

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1.

FLASHCARD QUESTION

Front

What is a multi-step equation?

Back

A multi-step equation is an equation that requires more than one step to solve. It often involves combining like terms, using the distributive property, and isolating the variable.

2.

FLASHCARD QUESTION

Front

What does it mean to have variables on both sides of an equation?

Back

Having variables on both sides of an equation means that the variable appears on both the left and right sides of the equation, requiring manipulation to isolate the variable.

3.

FLASHCARD QUESTION

Front

How do you solve the equation 4(k−2)=2(k−9)4(k-2)=2(k-9) ?

Back

1. Distribute: 4k−8=2k−184k - 8 = 2k - 18 2. Move variables to one side: 4k−2k=−18+84k - 2k = -18 + 8 3. Combine: 2k=−102k = -10 4. Divide: k=−5k = -5 .

4.

FLASHCARD QUESTION

Front

What is the first step in solving 8x+17=2x+358x + 17 = 2x + 35 ?

Back

The first step is to move all terms involving xx to one side and constant terms to the other side. This can be done by subtracting 2x2x from both sides.

5.

FLASHCARD QUESTION

Front

How do you isolate the variable in the equation −8(p+2)+p=4(p+3)+5-8(p+2)+p=4(p+3)+5 ?

Back

1. Distribute: −8p−16+p=4p+12+5-8p - 16 + p = 4p + 12 + 5 2. Combine like terms: −7p−16=4p+17-7p - 16 = 4p + 17 3. Move variables to one side: −7p−4p=17+16-7p - 4p = 17 + 16 4. Combine: −11p=33-11p = 33 5. Divide: p=−3p = -3 .

6.

FLASHCARD QUESTION

Front

What is the solution to the equation 12k+15=35+2k12k + 15 = 35 + 2k ?

Back

1. Move 2k2k to the left: 12k−2k+15=3512k - 2k + 15 = 35 2. Combine: 10k+15=3510k + 15 = 35 3. Subtract 15: 10k=2010k = 20 4. Divide: k=2k = 2 .

7.

FLASHCARD QUESTION

Front

What does the distributive property state?

Back

The distributive property states that a(b+c)=ab+aca(b + c) = ab + ac . It allows you to multiply a single term by two or more terms inside a set of parentheses.

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