
General Addition Rule of Probability
Flashcard
•
Mathematics
•
11th - 12th Grade
•
Practice Problem
•
Hard
Wayground Content
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15 questions
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1.
FLASHCARD QUESTION
Front
What is the General Addition Rule of Probability?
Back
The General Addition Rule states that for any two events A and B, the probability of A or B occurring is given by: P(A ∪ B) = P(A) + P(B) - P(A ∩ B).
2.
FLASHCARD QUESTION
Front
How do you calculate the probability of spinning purple or green on a spinner with 6 equal sections?
Back
To find the probability of spinning purple or green, count the favorable outcomes (e.g., 2 sections) and divide by the total outcomes (6). P(purple or green) = \frac{2}{6} = \frac{1}{3}.
3.
FLASHCARD QUESTION
Front
What is the probability of choosing a king or a club from a standard deck of 52 cards?
Back
There are 4 kings and 13 clubs, but one king is also a club. Using the General Addition Rule: P(king or club) = P(king) + P(club) - P(king and club) = \frac{4}{52} + \frac{13}{52} - \frac{1}{52} = \frac{16}{52}.
4.
FLASHCARD QUESTION
Front
What is the probability of choosing a card that is a spade or a 7?
Back
There are 13 spades and 4 sevens, but one of the sevens is a spade. Using the General Addition Rule: P(spade or 7) = P(spade) + P(7) - P(spade and 7) = \frac{13}{52} + \frac{4}{52} - \frac{1}{52} = \frac{16}{52}.
5.
FLASHCARD QUESTION
Front
If a jar contains 2 pink, 6 red, and 4 blue marbles, what is the probability of picking a red or blue marble?
Back
Total marbles = 2 + 6 + 4 = 12. Favorable outcomes (red or blue) = 6 + 4 = 10. P(red or blue) = \frac{10}{12} = \frac{5}{6}.
6.
FLASHCARD QUESTION
Front
What is the probability of spinning green or blue on a spinner with 12 equal sections?
Back
Assuming 5 sections are green and 2 are blue, P(green or blue) = \frac{5 + 2}{12} = \frac{7}{12}.
7.
FLASHCARD QUESTION
Front
Define mutually exclusive events in probability.
Back
Mutually exclusive events are events that cannot occur at the same time. For example, when flipping a coin, getting heads and tails are mutually exclusive.
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