Surface area of pyramids and cones

Flashcard
•
Mathematics
•
9th - 12th Grade
•
Hard
+1
Standards-aligned
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15 questions
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1.
FLASHCARD QUESTION
Front
What is the formula for the surface area of a square pyramid?
Back
The surface area (SA) of a square pyramid is given by the formula: SA = B + rac{1}{2}Pl, where B is the area of the base, P is the perimeter of the base, and l is the slant height.
Tags
CCSS.7.G.B.6
2.
FLASHCARD QUESTION
Front
What is the formula for the surface area of a cone?
Back
The surface area (SA) of a cone is given by the formula: SA = rac{1}{2}Pl + B, where P is the perimeter of the base, l is the slant height, and B is the area of the base.
3.
FLASHCARD QUESTION
Front
How do you calculate the area of the base of a square pyramid?
Back
The area of the base (B) of a square pyramid is calculated using the formula: B = s^2, where s is the length of one side of the square base.
Tags
CCSS.7.G.B.6
4.
FLASHCARD QUESTION
Front
What is the relationship between the slant height and the height of a pyramid?
Back
The slant height (l) of a pyramid is the distance from the apex to the midpoint of a side of the base. It can be found using the Pythagorean theorem: l = rac{1}{2}b^2 + h^2, where b is the base length and h is the height.
Tags
CCSS.HSG.SRT.C.8
5.
FLASHCARD QUESTION
Front
What is the perimeter of the base of a cone with radius r?
Back
The perimeter (P) of the base of a cone is calculated using the formula: P = 2 ext{π}r, where r is the radius of the base.
Tags
CCSS.7.G.B.4
6.
FLASHCARD QUESTION
Front
How do you find the surface area of a cone with a radius of 3 cm and a slant height of 5 cm?
Back
Using the formula SA = rac{1}{2}Pl + B, first calculate P = 2 ext{π}(3) = 6 ext{π} cm. Then, B = ext{π}(3^2) = 9 ext{π} cm². Finally, SA = rac{1}{2}(6 ext{π})(5) + 9 ext{π} = 15 ext{π} + 9 ext{π} = 24 ext{π} cm².
7.
FLASHCARD QUESTION
Front
What is the surface area of a cone with a radius of 4 cm and a height of 3 cm?
Back
First, find the slant height using the Pythagorean theorem: l = ext{√}(r^2 + h^2) = ext{√}(4^2 + 3^2) = 5 cm. Then, use the surface area formula: SA = rac{1}{2}(2 ext{π}(4))(5) + ext{π}(4^2) = 40 ext{π} cm².
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