Equation of Tangent Lines

Equation of Tangent Lines

Assessment

Flashcard

Mathematics

11th - 12th Grade

Hard

CCSS
HSF.IF.A.2

Standards-aligned

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15 questions

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1.

FLASHCARD QUESTION

Front

What is the definition of a tangent line?

Back

A tangent line to a curve at a given point is a straight line that touches the curve at that point and has the same slope as the curve at that point.

2.

FLASHCARD QUESTION

Front

How do you find the slope of a tangent line to a function at a specific point?

Back

The slope of the tangent line at a specific point can be found by calculating the derivative of the function at that point.

3.

FLASHCARD QUESTION

Front

What is the derivative of f(x) = -1(x + 12)^2 + 15?

Back

f'(x) = -2(x + 12).

4.

FLASHCARD QUESTION

Front

Calculate the derivative of f(x) = -1(x + 12)^2 + 15 at x = -9.

Back

f'(-9) = -2(-9 + 12) = -2(3) = -6.

5.

FLASHCARD QUESTION

Front

What is the point-slope form of a line?

Back

The point-slope form of a line is given by y - y1 = m(x - x1), where m is the slope and (x1, y1) is a point on the line.

6.

FLASHCARD QUESTION

Front

Using the point-slope form, write the equation of the tangent line to f(x) at x = -9.

Back

Using the point (-9, f(-9)) and slope -6, the equation is y - 15 = -6(x + 9).

7.

FLASHCARD QUESTION

Front

What is the value of f(-9) for the function f(x) = -1(x + 12)^2 + 15?

Back

f(-9) = -1(-9 + 12)^2 + 15 = -1(3)^2 + 15 = -9 + 15 = 6.

Tags

CCSS.HSF.IF.A.2

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