
Equation of Tangent Lines
Flashcard
•
Mathematics
•
11th - 12th Grade
•
Practice Problem
•
Hard
Standards-aligned
Wayground Content
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15 questions
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1.
FLASHCARD QUESTION
Front
What is the definition of a tangent line?
Back
A tangent line to a curve at a given point is a straight line that touches the curve at that point and has the same slope as the curve at that point.
2.
FLASHCARD QUESTION
Front
How do you find the slope of a tangent line to a function at a specific point?
Back
The slope of the tangent line at a specific point can be found by calculating the derivative of the function at that point.
3.
FLASHCARD QUESTION
Front
What is the derivative of f(x) = -1(x + 12)^2 + 15?
Back
f'(x) = -2(x + 12).
4.
FLASHCARD QUESTION
Front
Calculate the derivative of f(x) = -1(x + 12)^2 + 15 at x = -9.
Back
f'(-9) = -2(-9 + 12) = -2(3) = -6.
5.
FLASHCARD QUESTION
Front
What is the point-slope form of a line?
Back
The point-slope form of a line is given by y - y1 = m(x - x1), where m is the slope and (x1, y1) is a point on the line.
6.
FLASHCARD QUESTION
Front
Using the point-slope form, write the equation of the tangent line to f(x) at x = -9.
Back
Using the point (-9, f(-9)) and slope -6, the equation is y - 15 = -6(x + 9).
7.
FLASHCARD QUESTION
Front
What is the value of f(-9) for the function f(x) = -1(x + 12)^2 + 15?
Back
f(-9) = -1(-9 + 12)^2 + 15 = -1(3)^2 + 15 = -9 + 15 = 6.
Tags
CCSS.HSF.IF.A.2
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