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Implicit Differentiation and Derivatives Review

Implicit Differentiation and Derivatives Review

Assessment

Flashcard

•

Mathematics

•

9th - 12th Grade

•

Practice Problem

•

Hard

Created by

Wayground Content

FREE Resource

Student preview

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15 questions

Show all answers

1.

FLASHCARD QUESTION

Front

What is Implicit Differentiation?

Back

Implicit differentiation is a technique used to find the derivative of a function defined implicitly by an equation involving both x and y, without solving for y explicitly.

2.

FLASHCARD QUESTION

Front

What is the derivative of x3+y3=36x^3 + y^3 = 36 ?

Back

dydx=−x2y2\frac{dy}{dx} = -\frac{x^2}{y^2} .

3.

FLASHCARD QUESTION

Front

How do you find dydx\frac{dy}{dx} for 2x4y2−y3=72x^4y^2 - y^3 = 7 ?

Back

dydx=−8x3y24x4y−3y2\frac{dy}{dx} = -\frac{8x^3y^2}{4x^4y - 3y^2} .

4.

FLASHCARD QUESTION

Front

What is the derivative of f(x)=x2+xy+y3=0f(x) = x^2 + xy + y^3 = 0 ?

Back

dydx=−2x+yx+3y2\frac{dy}{dx} = -\frac{2x + y}{x + 3y^2} .

5.

FLASHCARD QUESTION

Front

What does dydx\frac{dy}{dx} represent?

Back

dydx\frac{dy}{dx} represents the rate of change of y with respect to x, or the slope of the tangent line to the curve at a given point.

6.

FLASHCARD QUESTION

Front

What is the chain rule in differentiation?

Back

The chain rule states that if a variable y depends on u, which in turn depends on x, then the derivative of y with respect to x is given by dydx=dydu⋅dudx\frac{dy}{dx} = \frac{dy}{du} \cdot \frac{du}{dx} .

7.

FLASHCARD QUESTION

Front

What is the product rule in differentiation?

Back

The product rule states that if you have two functions u(x) and v(x), then the derivative of their product is given by d(uv)dx=u′v+uv′\frac{d(uv)}{dx} = u'v + uv' .

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