Circles Unit Review

Circles Unit Review

Assessment

Flashcard

Mathematics

9th - 12th Grade

Practice Problem

Hard

Created by

Wayground Content

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15 questions

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1.

FLASHCARD QUESTION

Front

What is the area of a sector of a circle?

Back

The area of a sector is given by the formula: \( \text{Area} = \frac{\theta}{360} \times \pi r^2 \), where \( \theta \) is the angle in degrees and \( r \) is the radius.

2.

FLASHCARD QUESTION

Front

What is the formula for the circumference of a circle?

Back

The circumference of a circle is calculated using the formula: \( C = 2\pi r \) or \( C = \pi d \), where \( r \) is the radius and \( d \) is the diameter.

3.

FLASHCARD QUESTION

Front

What is the standard form of a circle's equation?

Back

The standard form of a circle's equation is: \( (x - h)^2 + (y - k)^2 = r^2 \), where \( (h, k) \) is the center and \( r \) is the radius.

4.

FLASHCARD QUESTION

Front

Convert the equation \( x^2 + y^2 - 22x - 20y - 4 = 0 \) to standard form.

Back

The standard form is: \( (x - 11)^2 + (y - 10)^2 = 225 \).

5.

FLASHCARD QUESTION

Front

What is the relationship between diameter and radius?

Back

The diameter is twice the length of the radius: \( d = 2r \).

6.

FLASHCARD QUESTION

Front

How do you find the area of a circle?

Back

The area of a circle is calculated using the formula: \( A = \pi r^2 \), where \( r \) is the radius.

7.

FLASHCARD QUESTION

Front

What is the formula for the area of a sector?

Back

The area of a sector is given by: \( \text{Area} = \frac{\theta}{360} \times \pi r^2 \), where \( \theta \) is the angle in degrees.

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