Circles Unit Review
Flashcard
•
Mathematics
•
9th - 12th Grade
•
Practice Problem
•
Hard
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1.
FLASHCARD QUESTION
Front
What is the area of a sector of a circle?
Back
The area of a sector is given by the formula: \( \text{Area} = \frac{\theta}{360} \times \pi r^2 \), where \( \theta \) is the angle in degrees and \( r \) is the radius.
2.
FLASHCARD QUESTION
Front
What is the formula for the circumference of a circle?
Back
The circumference of a circle is calculated using the formula: \( C = 2\pi r \) or \( C = \pi d \), where \( r \) is the radius and \( d \) is the diameter.
3.
FLASHCARD QUESTION
Front
What is the standard form of a circle's equation?
Back
The standard form of a circle's equation is: \( (x - h)^2 + (y - k)^2 = r^2 \), where \( (h, k) \) is the center and \( r \) is the radius.
4.
FLASHCARD QUESTION
Front
Convert the equation \( x^2 + y^2 - 22x - 20y - 4 = 0 \) to standard form.
Back
The standard form is: \( (x - 11)^2 + (y - 10)^2 = 225 \).
5.
FLASHCARD QUESTION
Front
What is the relationship between diameter and radius?
Back
The diameter is twice the length of the radius: \( d = 2r \).
6.
FLASHCARD QUESTION
Front
How do you find the area of a circle?
Back
The area of a circle is calculated using the formula: \( A = \pi r^2 \), where \( r \) is the radius.
7.
FLASHCARD QUESTION
Front
What is the formula for the area of a sector?
Back
The area of a sector is given by: \( \text{Area} = \frac{\theta}{360} \times \pi r^2 \), where \( \theta \) is the angle in degrees.
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