
Law of Sines / Law of Cosines
Flashcard
•
Mathematics
•
11th Grade
•
Practice Problem
•
Hard
+2
Standards-aligned
Wayground Content
FREE Resource
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16 questions
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1.
FLASHCARD QUESTION
Front
What is the Law of Sines?
Back
The Law of Sines states that in any triangle, the ratio of the length of a side to the sine of its opposite angle is constant. It can be expressed as: a/sin(A) = b/sin(B) = c/sin(C).
Tags
CCSS.HSG.SRT.D.10
CCSS.HSG.SRT.D.11
2.
FLASHCARD QUESTION
Front
What is the Law of Cosines?
Back
The Law of Cosines relates the lengths of the sides of a triangle to the cosine of one of its angles. It is expressed as: c² = a² + b² - 2ab*cos(C).
Tags
CCSS.HSG.SRT.D.10
CCSS.HSG.SRT.D.11
3.
FLASHCARD QUESTION
Front
When do you use the Law of Sines?
Back
The Law of Sines is used when you have either two angles and one side (AAS or ASA) or two sides and a non-included angle (SSA).
Tags
CCSS.HSG.SRT.D.10
CCSS.HSG.SRT.D.11
4.
FLASHCARD QUESTION
Front
When do you use the Law of Cosines?
Back
The Law of Cosines is used when you have two sides and the included angle (SAS) or all three sides (SSS) of a triangle.
Tags
CCSS.HSG.SRT.D.10
CCSS.HSG.SRT.D.11
5.
FLASHCARD QUESTION
Front
Calculate the length of side a if angle A = 30°, angle B = 45°, and side b = 10.
Back
a = b * (sin(A) / sin(B)) = 10 * (sin(30°) / sin(45°)) = 10 * (0.5 / 0.7071) ≈ 7.07.
Tags
CCSS.HSG.SRT.D.10
CCSS.HSG.SRT.D.11
6.
FLASHCARD QUESTION
Front
If side a = 8, side b = 6, and angle C = 60°, find side c using the Law of Cosines.
Back
c² = a² + b² - 2ab*cos(C) = 8² + 6² - 2*8*6*cos(60°) = 64 + 36 - 48 = 52. Thus, c ≈ 7.21.
Tags
CCSS.HSG.SRT.D.10
CCSS.HSG.SRT.D.11
7.
FLASHCARD QUESTION
Front
What is the sine of 90 degrees?
Back
The sine of 90 degrees is 1.
Tags
CCSS.HSG.SRT.C.7
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