Exponential Functions and Logarithms Flashcard Review

Flashcard
•
Mathematics
•
9th - 12th Grade
•
Hard
+2
Standards-aligned
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15 questions
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1.
FLASHCARD QUESTION
Front
What is the formula for calculating the effective annual rate (EAR) from the nominal interest rate compounded quarterly?
Back
The formula is: \( EAR = \left(1 + \frac{r}{n}\right)^{nt} - 1 \) where \( r \) is the nominal rate, \( n \) is the number of compounding periods per year, and \( t \) is the number of years.
2.
FLASHCARD QUESTION
Front
What is the future value formula for compound interest?
Back
The future value (FV) is calculated using the formula: \( FV = P \left(1 + \frac{r}{n}\right)^{nt} \) where \( P \) is the principal amount, \( r \) is the annual interest rate, \( n \) is the number of times interest is compounded per year, and \( t \) is the number of years.
3.
FLASHCARD QUESTION
Front
What is the present value formula for continuous compounding?
Back
The present value (PV) for continuous compounding is given by: \( PV = FV \cdot e^{-rt} \) where \( FV \) is the future value, \( r \) is the annual interest rate, and \( t \) is the time in years.
4.
FLASHCARD QUESTION
Front
What does it mean for a function to be exponential?
Back
An exponential function is a mathematical function of the form \( f(x) = a \cdot b^x \) where \( a \) is a constant, \( b \) is the base (a positive real number), and \( x \) is the exponent.
Tags
CCSS.HSF-LE.A.1A
5.
FLASHCARD QUESTION
Front
How do you determine the base of an exponential function from two points?
Back
To find the base \( b \) of an exponential function given two points \( (x_1, y_1) \) and \( (x_2, y_2) \), use the formula: \( b = \left(\frac{y_2}{y_1}\right)^{\frac{1}{x_2 - x_1}} \).
Tags
CCSS.HSF.LE.A.2
6.
FLASHCARD QUESTION
Front
What is the relationship between logarithms and exponents?
Back
Logarithms are the inverse operations of exponentiation. If \( b^y = x \), then \( \log_b(x) = y \).
Tags
CCSS.HSF.BF.B.5
7.
FLASHCARD QUESTION
Front
What is the change of base formula for logarithms?
Back
The change of base formula states: \( \log_b(a) = \frac{\log_k(a)}{\log_k(b)} \) for any positive base \( k \).
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