Search Header Logo
  1. Resource Library
  2. Math
  3. Trigonometry
  4. Pythagorean Theorem
  5. Pythagorean Theorem
Pythagorean Theorem

Pythagorean Theorem

Assessment

Flashcard

•

Mathematics

•

7th Grade

•

Practice Problem

•

Hard

•
CCSS
8.G.B.8, 8.G.B.7, 4.G.A.2

Standards-aligned

Created by

Wayground Content

FREE Resource

Student preview

quiz-placeholder

14 questions

Show all answers

1.

FLASHCARD QUESTION

Front

What is the Pythagorean Theorem?

Back

The Pythagorean Theorem states that in a right triangle, the square of the length of the hypotenuse (c) is equal to the sum of the squares of the lengths of the other two sides (a and b). It can be expressed as: a2+b2=c2a^2 + b^2 = c^2 .

Tags

CCSS.8.G.B.8

2.

FLASHCARD QUESTION

Front

What is the formula to find the length of the hypotenuse?

Back

To find the length of the hypotenuse (c) in a right triangle, use the formula: c=sqrt(a2+b2)c = \text{sqrt}(a^2 + b^2) .

Tags

CCSS.8.G.B.8

3.

FLASHCARD QUESTION

Front

What is the hypotenuse in a right triangle?

Back

The hypotenuse is the longest side of a right triangle, opposite the right angle.

4.

FLASHCARD QUESTION

Front

Which type of triangle does the Pythagorean Theorem apply to?

Back

The Pythagorean Theorem only applies to right triangles.

Tags

CCSS.8.G.B.8

5.

FLASHCARD QUESTION

Front

If one leg of a right triangle is 3 cm and the other leg is 4 cm, what is the length of the hypotenuse?

Back

Using the Pythagorean Theorem: c=sqrt(32+42)=sqrt(9+16)=sqrt(25)=5cmc = \text{sqrt}(3^2 + 4^2) = \text{sqrt}(9 + 16) = \text{sqrt}(25) = 5 cm .

Tags

CCSS.8.G.B.7

6.

FLASHCARD QUESTION

Front

What is the relationship between the sides of a right triangle?

Back

In a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

Tags

CCSS.8.G.B.8

7.

FLASHCARD QUESTION

Front

If the hypotenuse is 10 cm and one leg is 6 cm, how do you find the other leg?

Back

Use the formula: b=sqrt(c2−a2)b = \text{sqrt}(c^2 - a^2) . Here, b=sqrt(102−62)=sqrt(100−36)=sqrt(64)=8cmb = \text{sqrt}(10^2 - 6^2) = \text{sqrt}(100 - 36) = \text{sqrt}(64) = 8 cm .

Tags

CCSS.8.G.B.7

Access all questions and much more by creating a free account

Create resources

Host any resource

Get auto-graded reports

Google

Continue with Google

Email

Continue with Email

Microsoft

Continue with Microsoft

or continue with

Facebook

Facebook

Apple

Apple

Others

Others

By signing up, you agree to our Terms of Service & Privacy Policy

Already have an account?